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N76 [4]
3 years ago
5

What is the sum of the last four terms of the series 7+9+11+...+21

Mathematics
1 answer:
Doss [256]3 years ago
7 0
<span>7 - 9 = 2 9 - 11 = 2 You should see that the series just increases by +2 therefore you can figure out what the last four terms are and then add them up one of the last terms given is 21</span>
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Look at the graph of the linear function. On a coordinate plane, a line goes through 4 points. Point A is (negative 2, negative
kondor19780726 [428]

Using it's concept, the rate of change between point C and point D is of 2.

<h3>What is the average rate of change of a function?</h3>

The average rate of change of a function is given by the <u>change in the output divided by the change in the input</u>. Hence, over an interval [a,b], the rate is given as follows:

r = \frac{f(b) - f(a)}{b - a}

Considering the points of the given linear function, we have that:

  • Point C: f(1) = 2.
  • Point D: f(2) = 4.

Hence the rate of change between point C and point D is given by:

r = (4 - 2)/(2 - 1) = 2.

More can be learned about the average rate of change of a function at brainly.com/question/24313700

#SPJ1

4 0
1 year ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
How can you write 72+(8+19) to make it easier to add
max2010maxim [7]
There's a key problem in this question compelling you to actually rewrite it like that! Mathematically that is inaccurate and incorrect. If you do 72(8+19) it seems as if you are going to do 8+19*72 as in algebra whatever is outside the bracket is bound to go multiplied so technically (8+19)+72 would make more sense and the answer is

Using bidmas do the brackets first

8+19= 27
27+72=99
3 0
3 years ago
Read 2 more answers
In surveying families with pets, 5 out of 7 families owned a dog. If 35 families had dogs, how many families were surveyed?
Sliva [168]
Hello There!

Follow these steps:
35/5 = 7
7 x 7 = 49
35 out of 49 families owned a dog.
49 families were surveyed.

Hope This Helps You!
Good Luck :) 

- Hannah ❤

5 0
3 years ago
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Romashka [77]

Step-by-step explanation:

please check your question once and chose correct answer which one is helpful to you

4 0
3 years ago
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