The expression (2x2)3 is equivalent to _____. 6x2 6x5 8x6

A cafe makes ten 8-ounce fruit smoothies. Each smoothie is made with 4 ounces of soy milk and 1.3 ounces of banana flavoring. Th

RSB [31]

8-4-1.3=2.7
2.7 is the amount of blueberry juice used for one 8 ounce fruit smoothies so to get ten of them you multiply by 10
So 2.7x10=27 ounces of blueberry juice
1.3x10=13 ounces of banana flavoring
4x10=40 ounces of soy milk
Hope that helped

7 0

1 year ago

What is the length of the diagonal?

Juliette [100K]

Answer:

The value of x is equal to 26 cm.

Step-by-step explanation:

We can use the Pythagorean Theorem to solve this problem.

$a^2+b^2=c^2$

$a=10\\b=24\\c=?$

$10^2+24^2=c^2$

$100+576=c^2$

$676=c^2$

$\sqrt{676} =\sqrt{c^2}$

$26=c$

6 0

2 years ago

14=4x-6 <img src="https://tex.z-dn.net/?f=14%20%3D%204x%20-%206" id="TexFormula1" title="14 = 4x - 6" alt="14 = 4x - 6" align

Alex17521 [72]

Answer:

14=4x - 6

14+6=4x

20=4x

x=5

5 0

3 years ago

Write down the gradient of the line with equation y = 5X-8

k0ka [10]

Answer:

Let X be 2

Now,

y = 5*2 - 8

or, y= 10-8

or, y =2

Hope this will help please mark me as brainlest.

6 0

2 years ago

Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6

Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" = [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL = 0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0 ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0

2 years ago

The expression (2x2)3 is equivalent to _____.6x26x58x6