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sesenic [268]
3 years ago
5

The Sun and other stars orbit Earth.

Physics
1 answer:
ratelena [41]3 years ago
7 0
What is the question?
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How is an appliance's power related to the amount of energy it uses?
zysi [14]
The more powerful an appliance is, the more amounts of energy it uses. For instance a jack hammer that does not create a lot of destruction or change does not use a lot of energy. If a jack hammer that creates a lot of destruction and change probably uses a lot more energy and makes more sound.
6 0
3 years ago
Calculate the total mass of these letters in grams (mxe=131.29amu)
Lady_Fox [76]
We know avogadro's number = 6.023 x 10²³
1 amu = 1 atomic mass unit = 1/ (6.023 x 10²³) gm = 1.66 x 10⁻²⁴grams
<span>Now, to convert amu to grams,
 131.29 amu = 131.29 x 1.66 x 10</span>⁻²⁴grams
<span>= 2.18 x 10</span>⁻²²<span> grams is the answer</span>
4 0
4 years ago
Read 2 more answers
A&amp;P I need helppp <br> plspls
katrin2010 [14]

Answer:

c

Explanation:

6 0
3 years ago
The Nichrome wire is replaced by a wire of the same length and diameter, and same mobile electron density but with electron mobi
Marina CMI [18]

Answer:

The electric field inside the wire will remain the same or constant, while the drift velocity will by a factor of four.

Explanation:

Electron mobility, μ = \frac{v_d}{E}

where

v_d = Drift velocity

E = Electric field

Given that the electric field strength = 1.48 V/m,

Therefore since the electric potential depends on the length of the wire and the attached potential difference, then when the electron mobility is increased 4 times the Electric field E will be the same but the drift velocity will increase four times. That is

4·μ = \frac{4*v_d}{E}

6 0
3 years ago
Read 2 more answers
A solid sphere is rolling on a surface. what fraction of its total kinetic energy is in the form of rotational kinetic energy ab
drek231 [11]
<span>Total KE = KE (rotational) + KE (translational) Moment of inertia of sphere is I = (2/5)mr^2 So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2 KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2 Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2)) KE = (7/10) m x r^2 x w^2 Calculating the fraction of rotational kinetic energy to total kinetic energy, = rotational kinetic energy / total kinetic energy = (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7 The answer is 2 / 7</span>
7 0
3 years ago
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