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The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp

IRISSAK [1]

Answer:

a

$k = 11600000 N/m$

b

$\Delta L = 3.2323 *10^{-5} \ m$

c

$F = 3750.28 \ N$

Explanation:

From the question we are told that

The Young modulus is $E = 1.4 *10^{10} \ N/m^2$

The length is $L = 0.35 \ m$

The area is $2.9 \ cm^2 = 2.9 *10^{-4} \ m ^2$

Generally the force acting on the tibia is mathematically represented as

$F = \frac{E * A * \Delta L }{L}$ derived from young modulus equation

Now this force can also be mathematically represented as

$F = k * \Delta L$

So

$k = \frac{E * A }{L}$

substituting values

$k = \frac{1.4 *10^{10} * 2.9 *10^{-4} }{ 0.35}$

$k = 11600000 N/m$

Since the tibia support half the weight then the force experienced by the tibia is

$F_k = \frac{750 }{2} = 375 \ N$

From the above equation the extension (compression) is mathematically represented as

$\Delta L = \frac{ F_k * L }{ A * E }$

substituting values

$\Delta L = \frac{ 375 * 0.35 }{ (2.9 *10^{-4}) * 1.4*10^{10} }$

$\Delta L = 3.2323 *10^{-5} \ m$

From the above equation the maximum force is

$F = \frac{1.4*10^{10} * (2.9*10^{-4}) * 3.233*10^{-5} }{ 0.35}$

$F = 3750.28 \ N$

4 0

2 years ago

The indices of refraction for violet light (λ = 400 nm) and red light (λ = 700 nm) in diamond are 2.46 and 2.41, respectively. A

JulijaS [17]

Answer:

0.42°

Explanation:

Using Snell's law of refraction which states that the ratio of the angle of sin of incidence to angle of sine of refraction is equal to a constant for a given pair of media. Mathematically,

Sin(i)/sin(r) = n

n is the refractive index of the medium

FOR VIOLET LIGHT:

n = 2.46

i = 51°

r = ?

To get r, we will use the Snell's law formula.

2.46 = sin51°/sinr

Sinr = sin51°/2.46

Sinr = 0.316

r = sin^-1(0.316)

rv = 18.42°

FOR RED LIGHT:

n = 2.41

i = 51°

r = ?

To get r, we will use the Snell's law formula.

2.41 = sin51°/sinr

Sinr = sin51°/2.41

Sinr = 0.323

r = sin^-1(0.323)

rd = 18.84°

The angular separation between these two colors of light in the refracted ray will be the difference between there angle of refraction.

Angular separation = rd - rv

= 18.84° - 18.42°

= 0.42°

6 0

2 years ago

A woman exerts a horizontal force of 113 N on a crate with a mass of 31.2 kg.

sergeinik [125]

Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate doesn't move (static), acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = Fm - Ff = 0.

Fm is the applied force

Ff is the frictional force

Since Fm - Ff = 0

Fm = Ff

This means that the applied force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

R = 31.2 × 9.8

R = 305.76N

From the formula

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

8 0

2 years ago

Bill Nye help.. I didn’t get link to vid, hoping y’all have seen it. 20 POINTS!

Lyrx [107]

Answer:

Potential, Kinetic and Chemical energy.

Explanation:

btw, congratulations for turning into an expert.

6 0

3 years ago

HELP

Sergeu [11.5K]

Answer:

The answer is: To accelerate an object the force applied to the object has to increase.

Explanation:

the acceleration of an object increases with increased force and decreases with increased mass.

3 0

2 years ago