<em>60km</em><em>/</em><em>hr</em><em>.</em><em>.</em>
<em>I</em><em> </em><em>think</em><em> </em><em>so</em><em>.</em><em>.</em><em>.</em><em>.</em>
Electric field on the axis of ring on both sides is along the axial line
This electric field is away from the center on both sides
Now when an electron is placed on the axis of the ring then we will see that it will experience the electrostatic force on the electron.
The direction of force is always towards the center of the ring because here electron is a negatively charged particle and it will move opposite to the direction of electric field.
So as we release the electron from a distance of 30 cm the electron will move towards the center of ring and accelerate to its maximum speed till it will reach to the center of the ring
After that the electron will reach to the center of the ring and then moves out on the opposite side and then decelerate to zero speed as it will reach on other side.
Now after this it will again move towards the center of the ring and continue its motion similar way
So this is an oscillating motion about the center of the ring.
The answer is B because at the very top the acceleration is ZERO so it isn’t moving
Answer:
25 m/s
Explanation:
First of all, we can find the acceleration the object by using Newton's second law of motion:
where
F = 20.0 N is the net force applied on the object
m = 4.0 kg is the mass of the object
a is its acceleration
Solving for a, we find
Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration
t = 5 s is the time
By substituting,
