Answer:
342,000kg
Explanation:
p=mv
8.55*10^7 kg*m/s=m(900 km/h)
85,500,000 kg*m/s=m(900 km/h)
(85,500,000 kg*m/s)/(900 km/h)=m
Get same units.... 900km/h = 250m/s
m/s cancel in the division, you are left with just kg!!
85,500,000/250=342,000kg! That's it!
The answer is A it’s more safer that way
Inertia is the correct answer!
Answer:
the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>
Explanation:
Converting the angular speed into radians per second:
ω = 334 rpm · (2π rad / 1 rev) · (1 min / 60 s)
ω = 34.98 rad/s
The rotational kinetic energy of the blades is given by:
EK = 1/2 I ω²
where
- I is the moment of inertia
- ω is the angular speed
Therefore, rearranging the above equation, we get:
1/2 I ω² = EK
I ω² = 2 EK
I = 2(EK) / ω²
I = 2(4.55 × 10⁵ J) / (34.98 rad/s)²
<em>I = 743.71 kg·m²</em>
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Therefore, the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>.
Given Information:
Current in loop = I = 62 A
Magnitude of magnetic field = B = 1.20x10⁻⁴ T
Required Information:
Radius of the circular loop = r = ?
Answer:
Radius of the circular loop = 0.324 m
Explanation:
In a circular loop of wire with radius r and carrying a current I induces a magnetic field B which is given by
B = μ₀I/2r
Please note that for an infinitely straight long wire we use 2πr whereas for circular loop we use 2r
Where μ₀= 4πx10⁻⁷ is the permeability of free space
Re-arranging the equation yields
r = μ₀I/2B
r = 4πx10⁻⁷*62/2*1.20x10⁻⁴
r = 0.324 m
Therefore, the radius of this circular loop is 0.324 m
