3 years ago

21x^3 + 6x^2 - 28x - 8 factor this expression with work please?

Mathematics

2 answers:

Anit [1.1K]3 years ago

6 0

21x^3+6x^2-28x-8
(21x^3+6x^2)-(28X+8)
3x^2(7x+2)-4(7x+2)
3x^2-4=0 and 7x+2=0

marusya05 [52]3 years ago

3 0

$21x^3 + 6x^2 - 28x - 8 \\ \\ 3x^2 (7x + 2) - 4(7x + 2) \\ \\ (7x + 2)(3x^2 - 4) \\ \\$

The final result is: (7x + 2)(3x² - 4).

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