3 years ago

21x^3 + 6x^2 - 28x - 8 factor this expression with work please?

2 answers:

6 0

21x^3+6x^2-28x-8
(21x^3+6x^2)-(28X+8)
3x^2(7x+2)-4(7x+2)
3x^2-4=0 and 7x+2=0

3 0

$21x^3 + 6x^2 - 28x - 8 \\ \\ 3x^2 (7x + 2) - 4(7x + 2) \\ \\ (7x + 2)(3x^2 - 4) \\ \\$

The final result is: (7x + 2)(3x<span>² - 4).</span>

You might be interested in

postnew [5]

Answer:

Please see the attached picture ! :D

-------- HappY LearninG <3 ----------

8 0

2 years ago

Vladimir [108]

Answer:

Step-by-step explanation:

$\sqrt{ {( - 9 - - 1)}^{2} + {( - 6 - - 6)}^{2} }$

$\sqrt{ {( - 18)}^{2} }$

$\sqrt{324}$

3 0

2 years ago

diamong [38]

2x+2=-52
2x=-54
x=-27
That is the simple formula for it.

4 0

3 years ago

SIZIF [17.4K]

I'm assuming it's 10^6, so 10 would be the base, and 6 would be the exponent.

6 0

3 years ago

cluponka [151]

Answer:

2/3

Step-by-step explanation:

0.6 repeating as a fraction is 2/3

3 0

3 years ago