The answer is 46°.
The measure of an inscribed angle is equal to (1/2) the measure of the intercepted arc.
That means that, since ADC is 23 degrees, doubling that gives you 46 degrees, the measure of the intercepted arc.
Central angles are equal to the measure of the intercepted arc, which in this case is the same arc we just calculated.
Therefore it's 46.
Lets say the base is x and the height is y. The new base would be 1.2x and the new height would be 1.3y
Area of a triangle is base times height divided by 2:
1.2x*1.3y/2 = (1.2*1.3 + x*y)/2 = 1.56xy/2 = 0.78xy = 78% of xy
But a normal area would be 50% of xy
78% - 50% = 38%
ANSWER: 38% increase
5). Radius = 6 km. Circumference = 12π km. Area = 36π km²
6). Diameter = 8 mm. Circumference = 8π mm. Area = 16π mm²
20 because of the whole is 40 and the shaded part is by 20 you just take half of 40 and you get 20
As relative coordinates are asked so
8,-6 are the answer and each line is value of 2