Given the function f(x) = 20(1.25)^x . what is the average rate of change between f(2) and f(5)
2 answers:
The average rate of change of f(x) on the interval [a,b] is f(b)−f(a)b−a.
We have that a=1254, b=6103100, f(x)=20(54)x.
Thus, f(b)−f(a)b−a=20(54)(6103100)−(20(54)(1254))6103100−(1254)=−58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100.
Answer: the average rate of change is −58207660913467407226562517167001203595951472642–√5–√4+542101086242752217003726400434970855712890625197922048572373973475376871275743307366424750⋅53100≈550754.870532511
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