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dedylja [7]
3 years ago
14

Need help fast due tomorrow thanks

Mathematics
1 answer:
kirill [66]3 years ago
5 0

7;

2y^2-3y-1

8;

5m^2-13m+9

9;

k^2+9k

10;

2x^2-2x-5

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nadya68 [22]
B use the app Photomath it helps you with this kinda questions
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3 years ago
The mean shoe size of the students in a math class is 7. 5. Most of the shoe sizes fall within 1 standard deviation, or between
lana [24]

Answer: 1.5

Step-by-step explanation:Let the standard deviation of the shoe size be represented by ' ' and the mean shoe size be represented by ' = 7.5'. Also, the sizes of the shoe be represented by ' '. So, . Hence, the standard deviation of the shoe size data for the math class is 1.5.

4 0
2 years ago
PLEASE HELP!!!!!!<br> who every gets it right I will give brainly and 20 points
Sindrei [870]

Unit price:

$3.03 for a gallon of gass

$0.05 per ounce of soap

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8 0
2 years ago
I need help very important
siniylev [52]

Answer:

∠ EFG = 83°, ∠ GCE = 97°

Step-by-step explanation:

Since FE and FG are tangents to the circle then

∠ FGC and ∠ FEC are right angles

The sum of the angles in quadrilateral CEFG = 360°

Sum the 4 angles and equate to 360

3x + 11 + 90 + 5x - 23 + 90 = 360, that is

8x + 168 = 360 ( subtract 168 from both sides )

8x = 192 ( divide both sides by 8 )

x = 24

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∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°

4 0
3 years ago
A researcher surveyed 220 residents of a city about the number of hours they
olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 0.35, n = 220

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{0.35}{\sqrt{200}}

M = 0.0485

Margin of error of 0.0485 hours.

5 0
3 years ago
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