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3 years ago

Is 1/6 greater than 4/6

2 answers:

8 0

1/6 is greater than 4/6 because for example, if theres a pizza and theres only 6 pieces 1/6 would mean that you only ate one piece of it and 4/6 would mean that you ate 4 pieces. So, depends on the question. if its asking you if the the more it ate the greater then 4/6 would be greater but if its asking you the least it ate the greater then 1/6 is the answer, but it really depends on the question.

mars1129 [50]3 years ago

4 0

Yes it is 1/6 is bigger

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Can someone please help?

photoshop1234 [79]

Answer:

A. TRUE

B. TRUE

C. FALSE

that's all I know sorry

4 0

3 years ago

For what value(s) of k will the relation not be a function? A = {(3k−4, 16), (4k, 32)}

KiRa [710]

We won't have a function if for same value of x in (x,y) we get different values y.

So first step: figure out k so that the first coordinate (x) is the same:

3k-4=4k | solve for k

k = -4

no check the values y for the elements of the relation

x = 3k-4 = -12-4=-16

so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

Let me know if you have any questions.

7 0

3 years ago

Read 2 more answers

Graph the line for y+1=−3/5(x−4) on the coordinate plane.

Naddika [18.5K]

Please enclose that -3/5 in parentheses: y+1= (−3/5)(x−4)

Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:

y+1= (−3/5)(0−4) => y = -1 + 12/5 = -5/5 + 12/5 = 7/5. Plot (0, 7/5).

Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:

0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or x = 7/3. Plot (7/3, 0).

Now draw a straight line thru these two points.

6 0

3 years ago

Read 2 more answers

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the

Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}$

$0.001\sqrt{n} = 2.327*0.5$

$\sqrt{n} = \frac{2.327*0.5}{0.001}$

$(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}$

$n = 1353732.25$

Rounding up

A sample size of at least 1,353,733 is required.

5 0

4 years ago

Q and R are independent events. P(Q) = 0.4; P(Q AND R) = 0.08. Find P(R).

algol [13]

Because Q and R are independent, you have

$\mathbb P(Q\cap R)=\mathbb P(Q)\times\mathbb P(R)$
$0.08=0.4\times\mathbb P(R)$
$\implies \mathbb P(R)=0.2$

8 0

3 years ago