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3 years ago

For right triangle , triangle rst shown below, what is tan r

1 answer:

8 0

You know, it would really be helpful if we could have a peek at
the picture that's "shown below". Just a peek would be enough.
Right now, the only thing I see below is my dog.

Now ... follow me here ... if you're looking for tan(r), then 'r' is
one of the angles in the triangle, and I'm guessing that all three
of those letters are angles.

tan(r) is going to be the ratio of two of the sides ... I mean

(one side) divided by (another side).

There's no way to go any farther, because you haven't given us
any names for the sides, or any way to describe them.

Betcha the names of the sides are on that picture that's supposed
to be shown below.

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What is the area of the semicircle?

mihalych1998 [28]

Here's the link to the answer.. 69.08

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2 years ago

Use the diagram shown to answer the questions.

romanna [79]

Answer:

Step-by-step explanation:

First drop the line.

How many units is it from Point r to the x axis?

12.

How many units is it from Point r to the y axis?

Now we can use the Pythagorean Theorem.

$12^2+5^2=c^2 \\ \\ 144+25=c^2 \\ \\ c^2=169 \\ \\ c=13$

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2 years ago

Read 2 more answers

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IgorC [24]

B(x)=x2+3
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2 years ago

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

2 years ago

A jar contains six blue marbles and five red marbles. Suppose you choose a marble at random, and do not replace it. Then you ch

TEA [102]

The jar has 6+5=11 marbles.

We have to find the probability of the following event:

1.We pick a marble from a jar that has 11 marbles in total, 5 of them are red

2.We pick a marble from a jar that has now 10 marbles in total, 4 of them are red (because in the previous step we picked a red marble and did not put it back in the jar)

The probability of the first event is:

$P_1=\frac{5}{11}$

The probability of the second event is:

$P_2=\frac{4}{10}=\frac{2}{5}$

The probability of the both events to happen is:

$P=P_1\cdot P_2=\frac{5}{11}\cdot \frac{2}{5}=\frac{2}{11}=0.1818$

3 0

3 years ago