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alex41 [277]
3 years ago
13

The areas of two similar triangles are 49 cm2 and 16 cm2. what is the ratio of the corresponding side lengths? of the perimeters

?7 : 4; 7 : 1649 : 16; 16 : 497 : 4; 7 : 449 : 16; 49 : 4
Mathematics
1 answer:
Nikitich [7]3 years ago
4 0
We know that

[area of larger triangle]=[scale factor]²*[area of smaller triangle]
[scale factor]=√[area of larger triangle/area of smaller triangle]
[scale factor]=√[49/16]-----> 7/4

Part A) <span>what is the ratio of the corresponding side lengths?
the ratio </span>of the corresponding side lengths is equals to the scale factor

the answer Part A) is 
the ratio of the corresponding side lengths is 7/4

part B)what is the ratio of the perimeters?
 the ratio of the perimeters is equals to the scale factor

the answer Part B) is 
the ratio of the perimeters is 7/4
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sladkih [1.3K]
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D ) x^{1/3} * x^{1/3} * x^{1/3} = x
Therefore: B = D
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