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3 years ago

What is the determinant of m= {5 8 -5 4} ? 20 40 60 80

Mathematics

1 answer:

likoan [24]3 years ago

3 0

Answer:

Step-by-step explanation:

We have been given the matrix;

$\left[\begin{array}{ccc}5&8\\-5&4\end{array}\right]$

For a 2-by-2 matrix, the determinant is calculated as;

( product of elements in the leading diagonal) - (product of elements in the other diagonal)

determinant = ( 5*4) - (8*-5)

= 20 - (-40) = 60

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20 men decided to complete a work in 30 days. but after 6 days 8 men left now in how many day the work will be completed

Serga [27]

First, we convert it into a unit like this

20 workers × 30 days = 600 units work

After leaving the 5 workers, we have 35 days to complete the work.

In 35 days only 15 workers will do the work.

So the work completed in 35 days by 15 workers = 35 ×15 =525 units

Remaining unit = 600 -525 =75 units

This unit would do by 5 workers in (75/5) = 15 days.

So after 15 days, 5 workers should leave the job.

6 0

3 years ago

Solve for e E=mc2 m=3 C=6

ss7ja [257]

THe answer is 36
E=36

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3 years ago

In the diagram B is the midpoint of a A and C. B is also the midpoint or E and F. C is the midpoint of A and D.

aivan3 [116]

Answer:

AD = 84

Step-by-step explanation:

Since B is the midpoint of AC then AB = BC = 2x - 5

Since C is the midpoint of AD then AC = CD, thus

AB + BC = CD, that is

2x - 5 + 2x - 5 = x + 29

4x - 10 = x + 29 ( subtract x from both sides )

3x - 10 = 29 ( add 10 to both sides )

3x = 39 ( divide both sides by 3 )

x = 13

Hence

AD = AB + BC + CD

= 2x - 5 + 2x - 5 + x + 29 = 5x + 19, thus

AD = (5 × 13) + 19 = 65 + 19 = 84

6 0

3 years ago

Each pair of polygons is similar. Determine the transformations taht map one figure onto the other. Then find the missing side m

Gala2k [10]

Sdadsaafadfdfasdfasddsdfsgfvdfbhgcvv

3 0

3 years ago

Can't figure out this problem can anyone help if so thank you

Virty [35]

Answer:

10th term of the sequence = 0.537

Step-by-step explanation:

First three terms of the sequence are → 5, 4, $\frac{16}{5}$ ..........

Ratio of 2nd and 1st term of the sequence = $\frac{4}{5}$

Ratio of 3rd and 2nd term of the sequence = $\frac{\frac{16}{5} }{4}$

= $\frac{4}{5}$

Therefore, ratio between every successive term to the previous term is common.

Common ratio 'r' = $\frac{4}{5}$

First term of the sequence 'a' = 5

nth term of a geometric sequence = $a(r)^n$

Therefore, nth term of the given term will be $T_n=5(\frac{4}{5})^n$

Now we have to find the 10 term of the given sequence.

For n = 10,

$T_{10}=5(\frac{4}{5})^{10}$

= 0.53687

≈ 0.537

Therefore, 10th term of the sequence is 0.537

7 0

3 years ago