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Mumz [18]
3 years ago
14

How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 40% acid solution

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0

Let A be the amount of 100% acid.

100A+20*(6)=40*(A+6)

100A+120=40A+240

60A=120

A=2 gallons

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The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

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Let 2\cdot x_{1}+5\cdot x_{2} = -1\cdot h\cdot x_{1} + k\cdot x_{2} = 7, if this linear system has infinitely many solutions, then the following conditions must be met:

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\longrightarrow{\green{- 9 {x}^{2}   +  14x + 16}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\sqrt{49}  + [ \sqrt{81} - x \: (9x   -  14) ] \\ \\   =  \sqrt{7 \times 7}  + [ \sqrt{9 \times 9}   - 9 {x}^{2}   +  14x] \\  \\  =  \sqrt{( {7})^{2} }  + [ \sqrt{ ({9})^{2} }  - 9 {x}^{2}  +  14x ] \\  \\  (∵ \sqrt{ ({x})^{2} } = x ) \\  \\  = 7 + (9 - 9 {x}^{2}   + 14x) \\  \\  = 7 + 9 - 9 {x}^{2}   + 14x \\  \\  =  - 9 {x}^{2}   +  14x + 16

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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