Question

When testing for current in a cable with eleven ​color-coded wires, the author used a meter to test four wires at a time. How many different tests are required for every possible pairing of four ​wires? The number of tests required is nothing.

Answer 1

Answer:

The number of tests required is 330.

Step-by-step explanation:

We have to find the total number of combinations of four wires.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Four wires from a set of 11.

So

$C_{11,4} = \frac{11!}{4!(11-4)!} = 330$

The number of tests required is 330.