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vodka [1.7K]
3 years ago
11

Applicants who wish to be admitted to a certain professional school in a large university are required to take a screening test

devised by an educational testing service. From past results, the testing service has established that 70% of all applicants are eligible for admission and that 89% of those who are eligible for admission pass the exam, whereas 14% of those who are ineligible for admission pass the exam. (Round your answers to three decimal places.)
(a) What is the probability that an applicant for admission passed the exam?

(b) What is the probability that an applicant for admission who passed the exam was actually ineligible?
Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

Probability of eligible applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

Step-by-step explanation:

Total percentage eligible applicants who pass the exam

\textrm {89\%  of 70\%}= \dfrac{89\times70}{100}=62.3\%

Total  ineligible applicants  who pass the exam

\textrm {14\%  of 30\%}= \dfrac{14\times30}{100}=4.2\%

All applicants who pass this exam 62.3% + 4.2% = 66.5%

Probability of applicants who pass the exam

\textrm{probability }= \dfrac{66.5}{100}=0.665

Out of 66.5% applicants who pass the exam , 4.2% applicants are ineligible

\textrm{so the probability is}\dfrac{4.2}{66.5}=0.063

Probability of applicants who pass the exam is 0.665

probability of applicants who are ineligible but pass the exam 0.063

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Find the 7th term of the geometric sequence -5, 15, 45, 135, 405,...
katovenus [111]

Answer:

1,215

Step-by-step explanation:

Because if you think of it it multiplies by 3x so 3x5=? 15! 15x3=? 45! 45x3=? 405! 405x=3? 1,215! 1,215x3=? 3,645! anyways, I can go on and on I hope this answer was right!

7 0
3 years ago
Which expression could help you find the distance
Allisa [31]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

Correct Expression :

\qquad \tt \rightarrow \:  |10|  +  | - 6|

\qquad \tt \rightarrow \: distance = 16\:\: units\degree

____________________________________

\large \tt Solution  \: :

\textsf{Using distance formula -}

\qquad \tt \rightarrow \:  \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2}  }

\qquad \tt \rightarrow \:  \sqrt{( - 6 - 10) {}^{2}  + (4 - 4) {}^{2} }

\qquad \tt \rightarrow \:  \sqrt{( - 16) {}^{2}  + 0}

\qquad \tt \rightarrow \:  \sqrt{256}

\qquad \tt \rightarrow \: 16 \:  \: units

For short it can be expressed as :

\qquad \tt \rightarrow \:  |10|  +  | - 6|  = 10 + 6 = 16

[ y - coordinate of both the points are same ]

Correct option - D

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0
2 years ago
Geometry help? 4 questions so 40 points!!
san4es73 [151]
D
C
B
D

Hope I helped!
Giving me brainliest is much appreciated! =)

4 0
3 years ago
Read 2 more answers
Please help meeeeeeeeeeeeeee
Colt1911 [192]

Answer:

4/25 or 0.16

Step-by-step explanation:

your welcomeee

8 0
2 years ago
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How do i do this idk how to do
marysya [2.9K]

Let's find the perimeter first by adding all the side lengths together. There are two missing side lengths, which we can find by taking the side opposite them and subtract the side behind the missing side from them.

I've attached a diagram showing how to find the side lengths.

Now let's add all the side lengths together: 4 cm + 8 cm + 8 cm + 2 cm + 4 cm + 6 cm = 32 cm

The perimeter of this figure is 32 cm.

---

To find the area we can divide this figure into 2 rectangles. On the second attached diagram, I've split the figure into two and labeled the length and width of each rectangle.

Area of a rectangle = length * width

Area of red labeled rectangle = 4 cm * 2 cm = 8 cm²

Area of yellow labeled rectangle = 8 cm * 4 cm = 32 cm²

Add the two areas together: 8 + 32 = 40

The area of the figure is 40 cm².

6 0
3 years ago
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