Volume of cylinder diameter 10 inches height of 20 inches

1 answer:

4 0

$\sf{Volume~of~a~cylinder=\pi r^2h}\\\\V = \pi (\frac{10}{2})^2(20)\\\\V = 5^2 \pi (20)\\\\V = 25 \times 20 \pi\\\\\boxed{\bf{V = 500 \pi\approx1570.8}}$

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aivan3 [116]

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3 years ago

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lianna [129]

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2 years ago

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SashulF [63]

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6 0

2 years ago

sana is senior to Mona by 18 years after 6 years.Sana will be twice as old as Mona. find Mona,s percentage

Gwar [14]

Let
Present age of Sana = s
Present age of Mona = m

Sana is senior to Mona by 18 years
s=m+18............(1)

After 6 years
Sana will be = s+6
Mona will be = m+6
Then
Sana will be twice as old as Mona
(s+6)=2(m+6)
s+6=2m+12
s=2m+12-6
s=2m+6.............(2)
Put the value of s from (2) to (1)
2m+6=m+18
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Put the value of m in (1)
s=m+18
s=12+18
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Present age of Sana = s = 30 years old
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3 0

2 years ago

Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.

vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

$cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}$

$\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}$

4 0

2 years ago