Answer:
The answer is
<h2>( 1 , 2)</h2>
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
![M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )](https://tex.z-dn.net/?f=M%20%20%3D%20%28%20%5Cfrac%7Bx1%20%2B%20x2%7D%7B2%7D%20%2C%20%5C%3A%20%20%5Cfrac%7By1%20%2B%20y2%7D%7B2%7D%20%29)
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
M (4, 10) and N(-2,-6)
The midpoint is
![M = ( \frac{4 - 2}{2} , \: \frac{10 - 6}{2} ) \\ = ( \frac{2}{2} \: , \: \frac{4}{2} )](https://tex.z-dn.net/?f=M%20%3D%20%28%20%5Cfrac%7B4%20-%202%7D%7B2%7D%20%20%2C%20%5C%3A%20%20%5Cfrac%7B10%20-%206%7D%7B2%7D%20%29%20%5C%5C%20%20%3D%20%28%20%5Cfrac%7B2%7D%7B2%7D%20%20%5C%3A%20%2C%20%5C%3A%20%20%5Cfrac%7B4%7D%7B2%7D%20%29)
We have the final answer as
<h3>( 1 , 2)</h3>
Hope this helps you
She is going to 5 classes 3×5 = 15 and 15÷3=5
She has to score at least 86 on her fifth test.
Further explanation:
We will use the average formula to find the fifth value.
Given
![Average\ required=80\\x_1=81\\x_2=73\\x_3=84\\x_4=76\\x_5=?](https://tex.z-dn.net/?f=Average%5C%20required%3D80%5C%5Cx_1%3D81%5C%5Cx_2%3D73%5C%5Cx_3%3D84%5C%5Cx_4%3D76%5C%5Cx_5%3D%3F)
We have to find x5
The formula for average is:
![x=\frac{Sum\ of\ values}{Total\ number\ of\ values}\\Here,\\n=5\\So,\\x=\frac{x_1+x_2+x_3+x_4+x_5}{5}\\Putting\ values\\80=\frac{81+73+84+76+x_5}{5}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7BSum%5C%20of%5C%20values%7D%7BTotal%5C%20number%5C%20of%5C%20values%7D%5C%5CHere%2C%5C%5Cn%3D5%5C%5CSo%2C%5C%5Cx%3D%5Cfrac%7Bx_1%2Bx_2%2Bx_3%2Bx_4%2Bx_5%7D%7B5%7D%5C%5CPutting%5C%20values%5C%5C80%3D%5Cfrac%7B81%2B73%2B84%2B76%2Bx_5%7D%7B5%7D)
![80*5=314+x_5\\400=314+x_5\\x_5=400-314\\x_5=86](https://tex.z-dn.net/?f=80%2A5%3D314%2Bx_5%5C%5C400%3D314%2Bx_5%5C%5Cx_5%3D400-314%5C%5Cx_5%3D86)
She has to score at least 86 on her fifth test.
Keywords: Average, Word Problems
Learn more about average at:
#LearnwithBrainly
Answer:
2 x 20^2
Step-by-step explanation:
I did it on paper and looked it up to make sure