Someone Please help me. I don't understand how to do this. I need 34 points by Friday
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Answer:
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = 0.5932
Step-by-step explanation:
Step 1:-
by using normal distribution find the areas of given x₁ and x₂
Given The average watermelon weighs 8 lbs
μ = 8
standard deviation σ = 1.5
I) when x₁ = 6.8lbs and μ = 8 and σ = 1.5
ii) when x₂ = 9.3 lbs and μ = 8 and σ = 1.5
<u>Step2</u>:-
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = A(z₂) - A(-z₁)
= A(0.866) - A(-0.8)
= A(0.866)+ A(0.8)
check below normal table
= 0.3051 + 0.2881
= 0.5932
<u>Conclusion</u>:-
The probability that a watermelon will weigh between 6.8 lbs and 9.3 lbs.
P(6.8 ≤X≤9.3) = 0.5932
