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torisob [31]
3 years ago
6

When two substances that cannot dissolve each other are mixed, a mixture is formed. a heterogeneous mixture that has very small

dispersed particles and stays mixed for a long time is
a. a heterogeneous mixture that has larger dispersed particles that settle over time is
a?
Chemistry
2 answers:
skelet666 [1.2K]3 years ago
7 0
<h2>Answer 1) Colloids</h2><h3>Explanation : </h3>

When two substances that cannot dissolve each other are mixed, a mixture is formed. a heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is  a "Colloid"

An example of colloid can be gels, sols, or emulsions; where solids or liquids are dispersed in the mixture. It usually takes very long time to settle down.

<h2>Answer 2) Suspension</h2><h3>Explanation :</h3>

A heterogeneous mixture that has larger dispersed particles that settle over time is a "Suspension"

Suspensions are those mixtures which usually has large particles and which takes comparatively less time than colloids to get settled. Like salt water, muddy water, fine sand in water, etc.

Rudiy273 years ago
5 0
<h2>Answer:</h2>

a: The heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is colloid. Because colloid has particles that are small enough to suspended but are as large that they can scatter light.

b: A heterogeneous mixture that has large dispersed particles that settle over time is a suspension. Suspension can occur in liquids or gases but not in solids. There particles settle down slowly over time.

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Solid silver chloride, AgCI(s), decomposes to its elements when exposed to sunlight Write a balanced equation for this reaction
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Answer: The coefficient in front of AgCl when the equation is properly balanced is 2.

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4 years ago
I’ll give brainliest please help thanks.
oksano4ka [1.4K]

Answer:

See Explanation

Explanation:

The equation of the reaction is;

C7H16(g) + 11O2(g) ---->7CO2(g) + 8H2O(g)

1a) Number of moles in 228 g of H2O = 228 g/18 g/mol = 12.67 moles

From the reaction equation;

11 moles of O2 yields 8 moles of H2O

x moles of O2 yields 12.67 moles of H2O

x = 11 * 12.67/8

x = 17.4 moles of O2

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17.4 moles of O2 occupies 17.4 moles * 22.4 L/1 mole = 389.76 L

1b) Molar mass of C7H16 = 100 g/mol

Number of moles in 300 g of C7H16 = 300 g/100g/mol = 3 moles

1 mole of C7H16 yields 7 moles of CO2

3 moles of C7H16 yields 3 * 7/1 = 21 moles of CO2

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21 moles of CO2 occupies 21 moles * 22.4 L/1 mole = 470.4 L of CO2

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1 mole of H2 occupies 22.4 L

x moles of  H2 occupies 202 L

x = 1 mole * 202 L/22.4 L =  9 moles of H2

From the reaction equation;

3 moles of H2 yields 2 moles of PH3

9 moles of H2 will yield 9 * 2/3 = 6 moles of PH3

Mass of 6 moles of PH3 = 6 moles of PH3 * 34 g/mol = 204 g of PH3

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