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torisob [31]
4 years ago
6

When two substances that cannot dissolve each other are mixed, a mixture is formed. a heterogeneous mixture that has very small

dispersed particles and stays mixed for a long time is
a. a heterogeneous mixture that has larger dispersed particles that settle over time is
a?
Chemistry
2 answers:
skelet666 [1.2K]4 years ago
7 0
<h2>Answer 1) Colloids</h2><h3>Explanation : </h3>

When two substances that cannot dissolve each other are mixed, a mixture is formed. a heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is  a "Colloid"

An example of colloid can be gels, sols, or emulsions; where solids or liquids are dispersed in the mixture. It usually takes very long time to settle down.

<h2>Answer 2) Suspension</h2><h3>Explanation :</h3>

A heterogeneous mixture that has larger dispersed particles that settle over time is a "Suspension"

Suspensions are those mixtures which usually has large particles and which takes comparatively less time than colloids to get settled. Like salt water, muddy water, fine sand in water, etc.

Rudiy274 years ago
5 0
<h2>Answer:</h2>

a: The heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is colloid. Because colloid has particles that are small enough to suspended but are as large that they can scatter light.

b: A heterogeneous mixture that has large dispersed particles that settle over time is a suspension. Suspension can occur in liquids or gases but not in solids. There particles settle down slowly over time.

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Answer:

20.4g

Explanation:

First, we need to write a balanced equation for the reaction of butane to produce carbon dioxide.

When butane undergo Combustion, it will produce carbon dioxide and water as shown below:

2C4H10 + 13O2 —> 8CO2 + 10H2O

Molar Mass of C4H10 = (12x4) + (10x1) = 48 + 10 = 58g/mol

Mass of C4H10 from the balanced equation = 2 x 58 = 116g

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Mass of CO2 from the balanced equation = 8 x 44 = 352g

From the equation,

116g of C4H10 produced 352g of CO2.

Therefore, Xg of C4H10 will produce 61.9g of CO2 i.e

Xg of C4H10 = (61.9 x 116)/352 = 20.4g

Therefore, 20.4g of butane(C4H10) is needed to produce 61.9g of CO2

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