Mercury (ii) oxide is made up of mercury and oxygen. The total mass of mercury (ii) oxide is 14.2 g, after decomposition 13.2 g of mercury were formed, therefore the mass of oxygen 1 g (14.2 g -13.2 g).
Percentage of oxygen = (1/14.2)×100 = 7.04%
Percentage of mercury = (13.2/14.2) × 100 = 92.96%
Therefore, percentage composition of the compound, oxygen is 7.04% and mercury is 92.96%.
Answer:
2 mole of Sodium hydroxide reacts with 1 mole of Sulfuric acid
Explanation:
Write down the equation in the beginning with reactants and products:
NaOH + H₂SO₄ → Na₂SO₄ + H₂0
Now try to balance it. Try with Na first:
2NaOH + H₂SO₄ → Na₂SO₄ + H₂0
Na atoms are balanced. There are 6 Oxygen atoms on the right and 5 on the left. Balance by increasing the H₂O moles:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0
Check if H atoms are also balanced. They are. That means our final reaction is:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0
2 Moles of NaOH reacts with 1 mole of H₂SO₄
None because Covalent compounds don’t conduct electricity because they are formed between the non metal atoms by sharing of electrons. The Covalent compounds haves no free electrons and also no ions and hence they do not conduct electricity. That is why they do not conduct electricity.
Hello!
The balanced equation for the
neutralization of KOH is the following:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
To calculate the
volume of HCl required, we can apply the following equation:
So, the required volume of HCl is
541,54 mLHave a nice day!
Chemical bonds is the answer
