Answer:
B. 0.55 M
Explanation:
Step 1: Given data
- Moles of calcium chloride (solute): 1.5 mol
- Volume of solution: 2.75 M
Step 2: Calculate the molarity of the aqueous solution
The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.
M = moles of solute / liters of solution
M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M
The kinetic energy of emitted electrons when cesium is exposed to UV rays of frequency 1.80 * 10 ^15 is 3.054 x 10 ^- 19 J.
Explanation:
To calculate the kinetic energy of emitted electrons,
It is given that the frequency is 1.80* 10^15 Hz
We have,
KE = E – Eo = hv –hvo
Where, h = 6.626 x 10^ - 34 Js
Given frequency = 1.4 x 10 ^ 15 Hz
vo (Threshold frequency) for cesium = 9.39 x 10 ^ 14 Hz
Applying in equation,
we get
KE = 6.626 x 10^34 (1.4 x 10^15 - 9.39 x 10^14)
KE= 3.054 x 10^-19 J
[Note: Here, threshold frequency of Cesium is not provided. Apply the correct threshold frequency from the part A]
B. not fully absorbed by the atmosphere.
Explanation:
Visible light, which has a wavelength of between 380nm and 760nm is usually not fully absorbed by the atmosphere.
The earth's atmosphere is transparent to visible light emanating from the sun.
When visible light is radiated out from the sun, on reaching the atmospheric cover of the earth, it goes through without restraints.
- Little to no interaction occurs between the atmospheric cover of earth and visible light.
- This is why the surface is bright and receives sunlight.
- Other more energetic radiations interacts with atmosphere.
- Some of them gets cut off and some partially penetrate through.
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Answer:
257 F
Explanation:
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