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Alecsey [184]
2 years ago
11

When a strong acid such as hcl is added to the carbonic acid buffer system, _________

Chemistry
1 answer:
siniylev [52]2 years ago
8 0

When a strong acid such as HCl is added to the carbonic acid buffer system, <u>more </u><u>carbonic </u><u>acid is </u><u>formed</u><u>.</u>

<h3>What is a buffer system?</h3>

A buffer system prevent the pH change and resist it when an acid or base is added to the solution.

A buffer system is prepared by weak acid or weak base and their salts. There are three types of buffer system present.

  • Carbonic acid buffer
  • Plasma protein buffer
  • Phosphate buffer

Thus, the correct option is b. More carbonic acid is formed.

Learn more about buffer system

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Write the balanced NET IONIC equation for the reaction that occurs when ammonium nitrate and potassium hydroxide are combined. N
vova2212 [387]

Answer:

Net Ionic equation

NH₄⁺ + OH⁻ → NH₃ + H₂O

Option B is correct.

Weak Acid Strong Base

Check Explanation for the extent of the reaction.

Explanation:

Ammonium nitrate = NH₄NO₃

Potassium Hydroxide = KOH

Ammonium salts combine with alkalis to liberate NH₃ and form water.

The two reactants combine to give

NH₄NO₃ + KOH → KNO₃ + NH₃ + H₂O

In ionic form,

- NH₄NO₃ exists as NH₄⁺ and NO₃⁻

- KOH exists as K⁺ and OH⁻

- KNO₃ as K⁺ and NO₃⁻

And NH₃ and H₂O stay as they are, as per covalent compounds.

So, we have

NH₄⁺ + NO₃⁻ + K⁺ + OH⁻ → K⁺ + NO₃⁻ + NH₃ + H₂O

Eliminating the ions that exist on both sides, we have the net ionic equation to be

NH₄⁺ + OH⁻ → NH₃ + H₂O

which shows that this reaction is essentially a neutralization reaction in which the Bronsted Lowry acid, NH₄⁺, loses its proton to the base, OH⁻ and gives conjugate base, NH₃ and conjugate acid, H₂O.

This reaction is classified as a Weak acid versus Strong Base reaction as NH₄⁺ is from a Weak acid and OH⁻ is from a strong base.

Since this reaction is between a Weak base and a strong acid, the ionization isn't expected to be 100%, Hence, the extent of this reaction will be any option that is not 100%, a couple pieces of information might be required for the correct estimate, but above 50% seems correct.

Hope this Helps!!!

8 0
3 years ago
What object has a mass of 10 grams and a volume of 2 mL
Elena-2011 [213]

Answer:

Destiny = 5 g/ml

Explanation:

The formula for density is d=

Knowing this, divide your mass by volume:

10 g / 2 ml = 5 g/ml

Final answer:

Destiny = 5 g/ml

3 0
3 years ago
When the concentration of a substance differs from one area to another, this creates a concentration.
bija089 [108]

The difference in the concentration of a substance between two areas is called the concentration gradient. When a region has a higher particle concentration than another, this is known as a concentration gradient. A concentration gradient will cause particles in passive transport to diffuse down it from higher concentration to lower concentration until they are evenly spaced.

The gradual separation of a region of high density from a region of low density in a solution in terms of the concentration of a dissolved material. Understanding how ions and particles flow randomly in a solution or gas depends on the concentration gradient.

To learn more about concentration, click here.

brainly.com/question/10725862

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4 0
2 years ago
Hey ppl wassup <br> having a good day?
ludmilkaskok [199]
Yes how about you luv? how’s ur day going
3 0
3 years ago
Read 2 more answers
1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →
Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

  • The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

    If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

    But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.

  • 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

    As 80 g NaOH produces 106 g of Na₂CO₃.

    Therefore 5 g NaoH will produce ;

    106 / 80 x 5 = 6.625 g

Learn more about limiting reagent here ;

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5 0
2 years ago
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