The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams
<u><em>calculation</em></u>
2 KClO₃→ 2 KCl + 3O₂
Step 1: find the moles of O₂
moles = mass÷ molar mass
from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol
moles = 160 g÷ 32 g/mol = 5 moles
Step2 : use the mole ratio to determine the moles of KClO₃
from equation given KClO₃ : O₂ is 2:3
therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles
Step 3: find the mass of KClO₃
mass= moles x molar mass
from periodic table the molar mass of KClO₃
= 39 + 35.5 + (16 x3) =122.5 g/mol
mass = 3.333 moles x 122.5 g/mol =408.29 grams
Multiply 3 by the atomic mass of fluorine, forgive me if I’m wrong
Answer:
Average atomic mass = 6.96 amu.
Explanation:
Abundance of Li-6 = 4%
Abundance of Li-7 = 96%
Atomic mass of Li-6 = 6 amu
Atomic mass of Li-7 = 7 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (4×6)+(96×7) /100
Average atomic mass = 24 + 672 / 100
Average atomic mass = 696 / 100
Average atomic mass = 6.96 amu.
The helium in a glass model is a gas
Natural, Inorganic, Solid, Definite Chemical Composition, and Crystalline Structure. :)
