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zysi [14]
2 years ago
7

I apologize for the cut out on this picture. Here's the question: A company designs a container in the shape of a rectangular pr

ism for a fruit drink. The container has a base area of A, a height of h, and a volume of V. If the company decides to increase the height by 10% and reduce the area of the base by 10%, what will be the new volume of the container in terms of V.
A. 0.99V B. 1V C. 1.05V or D. 2V

Mathematics
1 answer:
Vikki [24]2 years ago
8 0

Step-by-step explanation:

Initial volume is given by,

V = A× h

When the height is increased by 10%, new height i.e h'

h' =  \frac{10}{100} h + h

h' =  \frac{1}{10}h + h

h' =  \frac{(1 + 10)}{10} h

h' =  \frac{11}{10} h

Similarly ,when the area of the base reduced by 10%, new area i.e A'

A' = A -  \frac{1}{10} A

A' =  \frac{9}{10} A

Therefore, new volume V'

V'= A'h'

V' =   \frac{9}{10} A \times   \frac{11}{10} h

V'= \frac{99}{100} Ah

V'= 0.99 V

optionA

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