What is the equation for the line that is perpendicular to y=3/4x+1, through (0,5)?

Mathematics

2 answers:

PtichkaEL [24]4 years ago

7 0

Answer:

The answer to your question is: y = -(4/3) + 5 or 4x + 3y - 15 = 0

Step-by-step explanation:

Data

y = (3/4)x + 1

Point = (0, 5)

Process

As the lines are perpendicular, then slope:

Original slope = 3/4

New slope = -(4/3)

Line

(y - y1) = m (x - x1)

( y - 5) = -(4/3) (x - 0)

3(y - 5) = -4(x)

3y - 15 = -4x

4x + 3y - 15 = 0

or 3y = -4x + 15

y = -(4/3) + 5

GREYUIT [131]4 years ago

5 0

The equation is y=-4/3x+5

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