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Alexandra [31]
3 years ago
11

PLEASE HELP ASAP!!! WILL MARK BRAINLIEST!!!!

Mathematics
1 answer:
crimeas [40]3 years ago
6 0

Answer:

Part 1) -\sqrt{15}

Part 2) x=\frac{b+ac}{2c-ab}

Step-by-step explanation:

Part 1) we know that

To put factor back into the square root, we have to put squared value

we have

-5\sqrt{0.6}

Remember that

5=\sqrt{5^2}

substitute in the expression above

-5\sqrt{0.6}=-\sqrt{(5^2)(0.6)}=-\sqrt{25*0.6}=-\sqrt{15}

Part 2) we have

\frac{2x-a}{b}=\frac{ax+1}{c}

Solve for x

That means----> Isolate the variable x

Multiply in cross

(2x-a)c=(ax+1)b

Apply distributive property

2cx-ac=abx+b

Group terms

2cx-abx=b+ac

Factor x left side

x(2c-ab)=b+ac

Divide by (2c-ab) both sides

x=\frac{b+ac}{2c-ab}

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