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3 years ago

Luke has 22 lots for sale. Each lot is 1.63 acres. How much land does Luke have for sale?

Mathematics

2 answers:

FromTheMoon [43]3 years ago

6 0

Answer: 35.86acres

Step-by-step explanation:

Luke has 22lots for sale

Each lot is 1.63acres

Since each lot is 1.63acres and there are 22lots

So Luke has

22×1.63acres

=35.86acres

nikklg [1K]3 years ago

5 0

Answer:

OC. 35.86 acres

Step-by-step explanation:

Given each lot is 1.63 acres

22 lots is therefore

= 22 x 1.63

= 35.86 acres

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Step-by-step explanation:

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5p coins weigh approximately 3 grams.

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Answer: 0.3 kg

Step-by-step explanation:

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4 years ago

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Plzzz I need help with this question I tried to solve it many times but I can't

blsea [12.9K]

Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as: $A1=\frac{(base)(height)}{2}$

Area of a rectangle is calculated as: $A2=(side)(side)$

Area of a right trapezoid is: $A3=\frac{(a+b)h}{2}$ , where:

a is short base

b is long base

h is height

1) Expressing areas in terms of x:

Area of triangle S1:

$S1=\frac{(2x-3)(4x-6)}{2}$

$S1=4x^{2}-12x+9$

Area of rectangle S2:

$S2 = (4x-6)(3x-2)$

$S2=12x^{2}-26x+12$

Area of trapezoid S3:

$S3=\frac{(2x+3+4x+1)(2x-3)}{2}$

$S3=\frac{(6x+4)(2x-3)}{2}$

$S3=6x^{2}-5x-6$

2) a) $S=4x^{2}-12x+9+12x^{2}-26x+12-(6x^{2}-5x-6)$

$S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6$

$S=10x^{2}-33x+37$

Which is the same as S = (2x-3)(5x-9)

b) For the areas to be the same:

$\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$32x^{2}-48x-28x+42=12x^{2}+8x-18x-12$

$20x^{2}-66x+54=0$

Using Bhaskara to solve the second degree equation:

$\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}$

$x_{1}=\frac{66+6}{40}$ = 1.8

$x_{2}=\frac{66-6}{40}$ = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) Expand a polynomial (or equation) is to multiply all the terms, remiving the parenthesis. Reduce a polynomial (or equation) is to combine terms alike,e.g.:

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$S=10x^{2}-18x-15x+27$ (expand)

$S=10x^{2}-33x+27$ (reduce)

d) For area of AFCG to be bigger than area of ADEB by 27:

$32x^{2}-48x-28x+42=12x^{2}+8x-18x-12+27$

$32x^{2}-48x-28x+42=12x^{2}+8x-18x+15$

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Solving:

$\frac{66+\sqrt{(-66)^{2}-(4.20.27)} }{2(20)}$

$\frac{66+46.86}{40}$

$x_{1}=\frac{66+46.86}{40}=$ 2.82

$x_{2}=\frac{66-46.86}{40}$ = 0.48

According to the enunciation, x cannot be less than 1.5, then, the value of x so that area AFGC exceeds the area ADEB by 27 is 2.82

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3 years ago

Explain how you can move the decimal point to convert 3,200 meters to kilometers

drek231 [11]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ You can move the decimal point one place. 1 meter = 0.001 km so we can move the decimal point one place.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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4 years ago

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dsp73

Answer:

first is 1/8, second is 1/10, third is 1/15, and fourth is 1/16

Step-by-step explanation:

1/2 divided by 4 = .5/4

.5/4 = 0.125

.125 = 1/8

1. 1/8

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.2/2 = .1

.1 = 1/10

2. 1/10

since 1/3 would be a repeating term, you can change 5 to 5/1

3/1 = 3

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.2/3 = 1/15

3. 1/15

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1 x 1 = 1

4 x 4 = 16

4. 1/16

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3 years ago