Find the zeros of the function and 2x² + 72=0

Mathematics

1 answer:

Natalija [7]4 years ago

6 0

Answer:

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ± $\sqrt{-36}$

= ±( $\sqrt{36(-1)}$ )

= ±( $\sqrt{36}$ × $\sqrt{-1}$ ) → $\sqrt{-1}$ = i

= ± 6i

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Graph the following equation using X- and y-intercepts.<br> x + y = -3

Kitty [74]

Answer:

x-intercept: (-3,0)

y-intercept: (0,-3)

Step-by-step explanation:

Looking at the equation, we can see that it is already in standard form, or in a $Ax+By=C$ format. Whenever a line is put into standard form, the x-intercepts are represented by $(\frac{C}{A},0)$ and the y-intercepts are represented by $(0, \frac{C}{B} )$ . So, let's calculate them by doing the following:

1) Find the x-intercept by using the $(\frac{C}{A},0)$ formula. Substitute the number on the right side of the equation for $C$ and the coefficient for the x term for $A$ . So, in this case, $C = -3$ and $A = 1$ :

$(\frac{C}{A},0)\\\\(\frac{-3}{1},0) \\(-3,0)$

Therefore, the x-intercept is (-3,0).

2) Next, find the y-intercept by using the $(0,\frac{C}{B} )$ formula and substituting the right values. $C$ is still the number on the right side of the equation and $B$ is the coefficient of the y term. So, $C = -3$ and $B = 1$ .