Question

Find the zeros of the function and 2x² + 72=0

Answer 1

Answer:

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ± $\sqrt{-36}$

  = ±( $\sqrt{36(-1)}$)

  = ±( $\sqrt{36}$ × $\sqrt{-1}$) → $\sqrt{-1}$ = i

  = ± 6i