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3 years ago

Find the zeros of the function and 2x² + 72=0

Mathematics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ± $\sqrt{-36}$

= ±( $\sqrt{36(-1)}$ )

= ±( $\sqrt{36}$ × $\sqrt{-1}$ ) → $\sqrt{-1}$ = i

= ± 6i

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victus00 [196]

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

In this question we need to solve the linear equation for each point, first for $(x,y) = (b, 1)$ and later for $(x,y) = (a, b)$ .

If we know that $(x,y) = (b, 1)$ , then the value of $b$ is:

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If we know that $(x,y) = (a, b)$ and $b = 3$ , then the value of $a$ is:

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The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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