Find the zeros of the function and 2x² + 72=0

Mathematics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ± $\sqrt{-36}$

= ±( $\sqrt{36(-1)}$ )

= ±( $\sqrt{36}$ × $\sqrt{-1}$ ) → $\sqrt{-1}$ = i

= ± 6i

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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