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max2010maxim [7]
3 years ago
10

Find the zeros of the function and 2x² + 72=0

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

Answer:

x = ± 6i

Step-by-step explanation:

Given

2x² + 72 = 0 ( subtract 72 from both sides )

2x² = - 72 ( divide both sides by 2 )

x² = - 36 ( take the square root of both sides )

x = ± \sqrt{-36}

  = ±( \sqrt{36(-1)})

  = ±( \sqrt{36} × \sqrt{-1}) → \sqrt{-1} = i

  = ± 6i

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