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Pavlova-9 [17]
2 years ago
6

A road bike has a wheel diameter of 622 mm. What is the circumference of the wheel? Use 3.14 for pi

Mathematics
2 answers:
Ghella [55]2 years ago
7 0

Answer:

Circumference ≅ 195 mm

Step-by-step explanation:

The circumference of a circle is equal to: 2*\pi *radius

Since Diameter = 2*radius we can replace that in the circumference equation giving us:

Circumference = \pi *Diameter

We know Diameter = 622 mm and pi = 3.14 so:

Circumference = \pi *Diameter = 3.14 * 622 mm = 195.308 mm

melisa1 [442]2 years ago
4 0

Answer:

the answer is d

Step-by-step explanation:

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Workout the circumstance of a circle with radius 9 cm take π to be 3.142 to 1 decimal place​
Goryan [66]

Answer:

C = 56.6 cm

Step-by-step explanation:

The circumference of a circle is

C = 2 * pi *r

C = 2 * 3.142 * 9

C =56.556

Rounded to 1 decimal place

C = 56.6 cm

5 0
2 years ago
se technology to solve 4x−11=3.2x+13. Enter the solutions in the boxes. Write the lesser solution first. Round to the nearest te
Zielflug [23.3K]

Answer: x=30

Step-by-step explanation: if you were looking for the value of x, hope this helps!

first, you have to make sure that the correct values are on the right side to allow us to find the answer faster and easier. your modified formula should look like this: 4x-3.2x=11+13

if you do the operations on each side, it will look like this: 0.8x=24, from here, all you have to do now is divide 24 by 0.8 to get the X value, which will result in 30!

8 0
3 years ago
What is 862,840 rounded to
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2 years ago
Determine the constant that must be added to the given expression to complete the square and express the resulting trinomial as
erma4kov [3.2K]
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8 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
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y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
2 years ago
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