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Serhud [2]
3 years ago
5

Assume that x is a double variable that has been initialized. Write a statement that prints it out, guaranteed to have a decimal

point, but without forcing scientific (also known as exponential or e-notation).
Computers and Technology
1 answer:
Feliz [49]3 years ago
6 0

Answer:

cout <<showpoint << x; is  the statement which  prints the decimal point,        but without forcing scientific.

Explanation:

The showpoint function in c++ print the decimal point number without forcing scientific.The showpoint function set  the showpoint format flag for the str stream in c++.

Following are the program in c++

#include<iostream> //header file

using namespace std; // namespace

int main() // main function

{

   double x=90.67; // double variable

   cout <<showpoint << x; // display x  without forcing scientific

  return 0;

}

Output

90.6700

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Declare a prototype for a function called isPrime that returns true or false and expects a single parameter named number of type
Sphinxa [80]

<u>Answer:</u>

<em>A prototype for a function called isPrime that returns is true.</em>

<u>Explanation:</u>

Function prototype is just a skeletal part of the function which has <em>a return type, function name and the respective parameters. </em>

There is a difference between function and function prototype.

Function is nothing but a <em>function definition</em>, where it actually has all the lines of codes which need to be processed when it is called. It can be invoked any number of times and anywhere within the<em> scope of the function</em>. <em> </em>

As per the given question, the prototype can be,

<em>bool isPrime (int); </em>

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Which IDEs support multiple high-level programming languages? Select all that apply.
nata0808 [166]

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6 0
3 years ago
Read 2 more answers
4.5 Code Practice
Alex787 [66]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

This program is written in C++.

                                                                         

#include <iostream>

using namespace std;

int main()

{

   

   string word;// variable for taking user input

   int cond;// to set condition true if user preses the stop and exit from loop

   

   cout<<"Enter word: \n";

   cin>>word;

   do// start while loop

   {

       

       

       if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit

       {

       cond=0;

       

       }

       else//otherwise loop continue

       {

           cout<<" You Entered "+ word +"\n";

           cout<<"Enter word: \n";

           cin>>word;

           cond=1;

       }

   }  

   while(cond == 1);// if user don't enter word "stop" loop run continuesly.  

   cout<<"Program exit";

   

   return 0;

}

5 0
3 years ago
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