Derek is involved in the option C.) work breakdown structure activity of providing insights about the design.
<h3>What is work breakdown structure?</h3>
A Work Breakdown Structure (WBS) is known to be a kind of an hierarchical outline or division of the tasks that is known to be needed to complete a given project.
Note that the WBS “breaks down” is seen as the structuring of any given project into a way that is said to be manageable in its deliverables.
Note also that the deliverable is sent on a task and as such, Derek is involved in the option C.) work breakdown structure activity of providing insights about the design.
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Derek, a project manager, needs to create a plan for a software development project. Which approach or document will help him define the tasks required to carry out that project?
A.) tracking application
B.) tracksheet
C.) work breakdown structure
D.) project application
Answer:
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Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Most worksheets are portrait orientation. A few of them are horizontal, but it depends on what you want to do.
Answer: This means that even though we believe the information is coming from a trusted source, it could still contract a virus due to someone else hacking it or the original sending not being aware of the virus.
Explanation: Just because information comes from a trusted/friendly source does not mean the information is clear of potential threats. Viruses are able to hide in information and the sending may not be aware that the virus is hiding in the information.
