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VMariaS [17]
3 years ago
9

Can some one fix this input ("Enter a number: ") print (num * 8)

Computers and Technology
1 answer:
Kaylis [27]3 years ago
6 0
If you save the input as num,
this will print the input 8 times.

num = input("Enter a number: ")
print(num * 8)

If you want to do actual math calculations,
then the input needs to be a number.

num = float(input("Enter a number: "))
print(num * 8)

This doesn't account for any errors in which the user doesn't input a number, but I don't think that's what you were looking for anyway :)
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Which of the following software programs provides for e-mail communication?. A. Access. B. Word Perfect. C. Outlook. D. Excel
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There are several software programs and internet applications that you use to send electronic mail (e-mail) to other people. However, for programs that are part of the Microsoft Suite, only one provides this ability, which is (C) Outlook.  

Microsoft Access is used to manage databases, while Microsoft Excel is used to analyze numerical and text data. WordPerfect is a word processor software created by Corel.  


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Shelby likes to play video games on an old Atari video game system. No matter how old the cartridge, when she inserts it into th
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ROM (Acronym of Read-only memory. (video games))

Explanation:

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Watson Studio is the IBM premier integrated development environment for data science and artificial intelligence practitioners.
fomenos

Answer:

c. Using the Data Refinery tool

Explanation:

Data wrangling and tidying in Data Science is the process whereby data to be analysed is obtained, cleaned and arranged before it is analysed in the environment.

Since Watson Studio happens to be an IBM premier integrated development environment for data science and artificial intelligence practitioners, there is need for them to have data softwares to make data scientists practitioners' works easier.

<em>In this scenario, the best tools to aid in tidying data in the Watson studio would be the use of </em><u><em>Data Refinery Tool.</em></u>

3 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

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Example of Bandwidth Analogies: using Pipe
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Answer:

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