Prove: the sum of four consecutive integers is never divisible by 4 g

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

$n+n+1+n+2+n+3=4n+6$

4n is divisible by 4, but 6 is not, so the sum 4n+6 is not divisble by 4.

Nastasia [14]3 years ago

6 0

Yup, that's right. Your integers are n,n+1,n+2,n+3. You add them up to get 4n+6. If you don't want to talk about remainders or congreuences, then you can also say that 4n+64=n+64=n+1+12. And ...
Missing: g

You might be interested in

How do you solve 1/2 / -2/5 + (-1/4)

nekit [7.7K]

<span>1/2 / -2/5 + (-1/4)
= 1/2 * (-5/2) - 1/4
= -5/4 - 1/4
= -6/4
= -3/2

hope it helps</span>

8 0

4 years ago

Read 2 more answers

Which expression represents 100 divided by an unknown number?

Kazeer [188]

B I'm pretty sure since p is the unknown number.

6 0

3 years ago

Read 2 more answers

What is pi <br> 3.15<br> 3.75<br> 3.14

andrey2020 [161]

Your question;
<span>What is pi?
My answer;
Pi or </span>π is commonly known as 3.14
Hope I helped,
♥ James

6 0

4 years ago

Read 2 more answers

the sum of the first ten terms of a linear sequence is -60 and the sum of the first fifteen terms is -165. Find the 18th term of

const2013 [10]

Answer:

Step-by-step explanation:

$S_{10}=\dfrac{2a_1+d(10-1)}{2}\cdot 10\\\\\dfrac{2a_1+9d}{2}\cdot 10=-60\\\\\dfrac{2a_1+9d}{2}=-6\\\\2a_1+9d=-12\\\\2a_1=-12-9d\\\\\\S_{15}=\dfrac{2a_1+d(15-1)}{2}\cdot 15\\\\\dfrac{2a_1+14d}{2}\cdot 15=-165\\\\\dfrac{2a_1+14d}{2}=-11\\\\2a_1+14d=-22\\\\-12-9d+14d=-22\\\\ 5d=-10 \\\\ d=-2\\\\\\2a_1=-12-9(-2)=-12+18=6\\\\a_1=3\\\\\\ a_{18}=a_1+17d=3+17(-2)=3-34=-31$

8 0

3 years ago

What does it mean for triangles to be congruent?

siniylev [52]

SAS (Side-Angle-Side): If two pairs of sides of two triangles are equal in length, and the included angles are equal in measurement, then the triangles are congruent. SSS (Side-Side-Side): If three pairs of sides of two triangles are equal in length, then the triangles are congruent.

8 0

4 years ago