Help plzzzzzzz......

Mathematics

1 answer:

Veronika [31]2 years ago

8 0

Answer:

A. England = 56000000

B. 1.046 * 10^7

C. 9.7 to 2sf

Step-by-step explanation:

A. England = 5.60*10000000

=56000000

B. Wale = 3.14*1000000 = 3140000

Scotland = 5.44*1000000 = 5440000

Northern Ireland = 1.88*1000000 =1880000

Total = 10460000

In standard form =1.046*10^7

C. Total population as at 2018 = 66460000

expected population by 2041 = 72900000

increase or change = (72900000 - 66460000) = 6440000

% change = (6440000/66460000)*100

= 0.0969003912 * 100

= 9.69003912

= 9.7 to 2sf

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3 years ago

Jose collects baseball cards. Over the last year, the change in the value of his favorite card is $-7. Which best describes the

natali 33 [55]

Answer with explanation:

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Here, positive value indicates gain or above something where as negative value indicates loss or below something.

If the change in the value of his favorite card is $-7, that simply indicates that he is having a loss of $-7 that can be understand as the value of his this years card must be smaller than the last year card.

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2 years ago

What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)? –2x + 5 2x – 5 –2x – 5 2x + 5

juin [17]

ANSWER

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = - 2x+5$

EXPLANATION

We have been given the quotient,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} }$
to simplify.

We need to rewrite the numerator as difference of two cubes.

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ {5}^{3} - ( {2x})^{3} }{ 25 + 10x + 4 {x}^{2} }$

We need to make use of the difference of cubes formula,

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

We now let,
$a = 5 \: and \: b = 2x$

Then the numerator becomes,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 5 (2x) + {(2x)}^{2}) }{ 25 + 10x + 4 {x}^{2} }$

This simplifies to,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 10x + 4 {x}^{2}) }{ 25 + 10x + 4 {x}^{2} }$

We cancel out common factors to obtain,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)}{ 1}$

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = 5 - 2x$