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3 years ago

HELP PLEASE ASAP 55 POINTS I BEG YOU!!!!!!

Mathematics

1 answer:

Alja [10]3 years ago

3 0

Answer:1 b+1T+1 U=5617b+1 T =9062b+7T+5U = 1758

Step-by-step explanation:

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Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x2 + 1 inches, and

Rasek [7]

19.25 inches I think i.t is

8 0

4 years ago

Read 2 more answers

20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st

Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that $p = 0.13$

14 drivers are stopped

This means that $n = 14$

(a) None will have an invalid license.

This is $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423$

(b) Exactly one will have an invalid license.

This is $P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977$

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

$P(X < 2) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56$

8 0

3 years ago

Pls help me to solve this

zloy xaker [14]

Answer:

see below

Step-by-step explanation:

19-3 will be greater

We are multiplying 1/2 *(19-3) which is multiplying by a number less than 1 it will be less than 1

18-3 = 16

1/2 * (19-3)

Using PEMDAS

We do parentheses first

1/2 ( 16)

Then multiply

4 0

3 years ago

I need G PLZZZZZZZZZZZZZZZ

klasskru [66]

I can’t even read it

3 0

3 years ago

2. Kelsea needs a test average of at least 90 to get an "A-" this marking period in math. Her three test grades

Luda [366]

Answer:

Equation: 87 + 91 + 86 + x = 360

Solution: 264 + x = 360

x = 360 - 264

x = 96

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

First three Kelsea's test grades : 87, 91 and 86

2. What score must she get on her fourth test to receive at least an A- ?

Define variable: x that represents the grade needed by Kelsea on her fourth test to receive at least an A-

Equation: 87 + 91 + 86 + x = 360

Solution: 264 + x = 360

x = 360 - 264

x = 96

Now you can understand if the previous work you did is correct

6 0

4 years ago