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Elis [28]
3 years ago
11

Line segment SU is dilated to create S'U' using the dilation rule DQ,2.5.

Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0

Answer:

C ( 6 units

Step-by-step explanation:

just took the quiz

seropon [69]3 years ago
4 0

Answer:

6 units on edg 2020

Step-by-step explanation:

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Please help ASAP!!! Will give brainlist :)
Furkat [3]

Answer:

A': (2,1)

B': (5,3)

C': (4,-1)

x -----> x + 1

y -----> y - 2

4 0
2 years ago
What is the answer of 7 copies of the sum of 8/5 + 4
kotykmax [81]
To solve (8/5 + 4)7, you first have to add 8/5+4.  But you cannot simply add the too because they have to be in a common denominator 'form'.  To do that, we find a common denominator which is 5.  We then multiply 4/1 by 5.
8/5 + 4/1= 8/5 +20/5.
Now you can solve; 8+20= 28.  You leave the denominator as 5.
You get 28/5 and now you have to multiply it by 7/1.  Another of saying 28/5 is 5 3/5.  So 5 3/5 x 7/1= 39 2/10 (final answer)

4 0
3 years ago
Which transformation can be used to prove Similarity and why?
lyudmila [28]
A similarity transformation is one or more rigid transformations (reflection, rotation, translation) followed by a dilation. When a figure is transformed by a similarity transformation, an image is created that is similar to the original figure. In other words, two figures are similar if a similarity transformation will carry the first figure to the second figure.
7 0
2 years ago
The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
2 years ago
the number of hours,h, it takes to wash c numbers of cars at a school fundraiser is inversely proportional to the number of stud
Alex787 [66]
\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\stackrel{\textit{\underline{h}ours to wash a car, is inversely proportional to \underline{s}tudents working on it}}{h=\cfrac{k}{s}}
3 0
2 years ago
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