Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
To do this, you got to square 256.
The square root of 256 is 16.
Therefore, there are 16 small squares on each edge of the mosaic.
Kinda proof:
o o o o O
o o o o O
o o o o O
o o o o O
o o o o O
25 squares. Square root is 5. 5 along each edge. My work shares same concept.
Extremely unnecessary proof:
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
o o o o o o o o o o o o o o o O
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There are 256 squares, and you can count 16 on each edge. this shows 16 times 16, or 16 squared, which is 256.
I got ten. Here's the equation.
x = 1/2x + 5
<span>Subtract 1/2x from both sides to get all x's on one side </span>
<span>x - 1/2x = 1/2x - 1/2x + 5 </span>
<span>1/2x = 5 </span>
<span>Now multiple the left by 2 to get x, but since it's an equation, you need to also multiply the right by 2 to keep it =. </span>
<span>2 * 1/2x = 2 * 5 </span>
<span>x = 10 cats</span>
The product of 5 and n is written as 
.
Two less than this product is 
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
