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2 years ago

Solve the quadratic equation.m^2/15 -3 = 2

Mathematics

1 answer:

Radda [10]2 years ago

7 0

The answer is $5 \sqrt{3}$

<h3>Explanation :</h3>

$\frac{ {m}^{2} }{15} - 3 = 2$

$\frac{ {m}^{2} }{15} = 2 + 3$

$\frac{ {m}^{2} }{15} = 5$

${m}^{2} = 5 \times 15$

${m}^{2} = 75$

$m = \sqrt{75}$

$m = \sqrt{25 \times 3}$

$m = \sqrt{25} \times \sqrt{3}$

$m = 5 \sqrt{3}$

CMIIW

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Worksheet Check

Maurinko [17]

Hey i think the only mistake i caught was when you put 3 points under the line mark instead of only needing 2.
Possibly another mistake at 3a, Only 2 points (but i could be wrong)

6 0

2 years ago

I need help on this please

ziro4ka [17]

Answer:

See answers below

Step-by-step explanation:

From the given functions, the equivalent function for when x = 0 is -(x-1)²

h(x) = -(x-1)²

h(0) = -(0-1)²

h(0)= -(-1)²

h(0) = -1

when x = 2, the equivalent function is -1/2x - 1

h(x) = -1/2x - 1

h(2) = -1/2(2) - 1

h(2) = -1-1

h(2) = -2

when x = 5, the equivalent function is -1/2x - 1

h(x) = -1/2x - 1

h(5) = -1/2(5) - 1

h(5) = -5/2-1

h(5) = -7/2

3 0

3 years ago

Complete the table for the function y=x+3 <br><br> x - y <br> 0 -<br> 2 -<br> 4 - <br> 6 -

Rus_ich [418]

For each x value, add 3 to get y values.
0+3=3
2+3=5
4+3=7
6+3=9

Final answers, respectively: 3,5,7,9

7 0

3 years ago

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago

Thank you to all the people who helped! :)

ira [324]

Answer:

Oh my gosh!

Step-by-step explanation:

Good job, nice!

4 0

3 years ago

Read 2 more answers

Solve the quadratic equation.m^2/15 -3 = 2​

Solve the quadratic equation.m^2/15 -3 = 2