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Svet_ta [14]
3 years ago
9

Given a 10-V power supply, would a 20-ohm resistor and a 5-ohm resistor need to be arranged in parallel or in series to generate

a current of 2.5 A? How much current would move through each resistor? In 3-4 sentences, answer each question and explain your answers
Physics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

The arrangement of the resistors to generate a current of 2.5 A is  a parallel arrangement and the current flowing the first resistor is  I_1 =  0.5 \ A   while the current flowing through the second resistor is  I_2 =  2 \ A

Explanation:

From the question we are told that

   The voltage is  V = 10 \  V

   The first resistor is  R_1 = 20 \ \Omega

    The second resistor is  R_2 = 5 \ \Omega

    The current is  I = 2.5 \  A

Generally the resistance of the circuit is mathematically evaluated as

      R = \frac{V}{I}

=>   R = \frac{10 }{2.5}

=>   R = 4 \ \Omega

When the given resistors are connected in series the resistance is  

     R_e =  R_1 + R_2

=>  R_e = 20 + 5    

=>  R_e = 25 \ \Omega

Generally when the resistors are connected in parallel the resistance is  

      R_e  =  \frac{R_1 * R_2}{R_1 + R_2}    

=>    R_e  =  \frac{20  * 5}{20  + 5}    

=>    R_e  = 4 \ \Omega

The current flowing through resistor 1 is mathematically represented as

      I_1 =  \frac{V}{R_1}  

=>  I_1 =  \frac{10}{20 }  

=>  I_1 =  0.5 \ A  

The current flowing through resistor 1 is mathematically represented as

      I_2 =  \frac{V}{R_2}  

=>  I_1 =  \frac{5}{20 }  

=>  I_2 =  2 \ A

The arrangement of the resistors to generate a current of 2.5 A is  a parallel arrangement and the current flowing the first resistor is  I_1 =  0.5 \ A   while the current flowing through the second resistor is  I_2 =  2 \ A

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