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Dafna1 [17]
4 years ago
12

What is a gravitational force? give two examples to illustrate it.

Physics
2 answers:
fredd [130]4 years ago
7 0

Answer:

The gravitational force is a force that attracts any two objects with mass.

Explanation:

Some examples of the force of gravity include: The force that holds the gases in the sun. The force that causes a ball you throw in the air to come down again.

alexandr402 [8]4 years ago
3 0

Answer:

Some example of the force of gravity include:the force that hold the gases in the sun.

Explanation:

The force that causes a ball you throw in the air to come down again.the force that cause a car to coast downhill even when you aren't stepping on the gas.The gravitational force is the force that attract any object with mass.

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Select all the correct answers. The eight planets in alphabetical order are Earth, Jupiter, Mars, Mercury, Neptune, Saturn, Uran
Rainbow [258]

Answer:

The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune

Explanation:

4 0
3 years ago
Read 2 more answers
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.
zmey [24]

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

3 0
4 years ago
Which of the following particles is similar to a He nucleus?
Marat540 [252]
<h2>Answer:</h2>

Alpha

<em>I hope this helps you</em>

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4 0
2 years ago
Read 2 more answers
1.Energy is used when a force acts over a.....................
Leona [35]

Answer:

the same mass answer b) but i dont know first question

5 0
3 years ago
If 5.4 J of work is needed to stretch a spring from 15 cm to 21 cm and another 9 J is needed to stretch it from 21 cm to 27 cm,
qaws [65]

Answer:

the natural length of the spring is 9 cm

Explanation:

let the natural length of the spring = L

For each of the work done, we set up an integral equation;

5.4 = \int\limits^{21-l}_{15-l} {kx} \, dx \\\\5.4 = [\frac{1}{2}kx^2 ]^{21-l}_{15-l}\\\\5.4 = \frac{k}{2} [(21-l)^2 - (15-l)^2]\\\\k = \frac{2(5.4)}{(21-l)^2 - (15-l)^2}  \ \ \ -----(1)

The second equation of work done is set up as follows;

9 = \int\limits^{27-l}_{21-l} {kx} \, dx \\\\9 = [\frac{1}{2}kx^2 ]^{27-l}_{21-l}\\\\9 = \frac{k}{2} [(27-l)^2 - (21-l)^2] \\\\k = \frac{2(9)}{(27-l)^2 - (21-l)^2} \ \ \ -----(2)

solve equation (1) and equation (2) together;

\frac{2(9)}{(27-l)^2 - (21-l)^2} = \frac{2(5.4)}{(21-l)^2 - (15-l)^2}\\\\\frac{2(9)}{2(5.4)} = \frac{(27-l)^2 - (21-l)^2}{(21-l)^2 - (15-l)^2}\\\\\frac{9}{5.4} = \frac{(729 - 54l+ l^2) - (441-42l+ l^2)}{(441-42l+ l^2) - (225 -30l+ l^2)} \\\\\frac{9}{5.4 } = \frac{288-12l}{216-12l} \\\\\frac{9}{5.4 } =\frac{12}{12}  (\frac{24-l}{18 -l})\\\\\frac{9}{5.4 } = \frac{24-l}{18 -l}\\\\9(18-l) = 5.4(24-l)\\\\162-9l = 129.6-5.4l\\\\162-129.6 = 9l - 5.4 l\\\\32.4 = 3.6 l\\\\l = \frac{32.4}{3.6} \\\\

l = 9 \ cm

Therefore, the natural length of the spring is 9 cm

4 0
3 years ago
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