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kogti [31]
3 years ago
5

Line segment AB is dilated to create line segment A'B' using point Q as the center of dilation.

Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Rashid [163]3 years ago
7 0

Answer:

2

Step-by-step explanation:

To find the scale of dilation, you have to compare the ratio of the after transform with before transform according to the center of dilation. In this case, the center of dilation is Q so you have to compare QA' : QA. We know that QA= 1.25 and AA' is 1.25. The distance of QA' will be:

QA'= QA + AA'= 1.25 + 1.25 = 2.5

The scale factor will be:

scale factor= QA' : QA.= 2.5 : 1.25

scale factor= 2

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Leokris [45]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Please help me!!!!!!!!!
Serga [27]

Answer:

Step-by-step explanation:

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3 years ago
6-2/3(x+5)=4x solve for x
laiz [17]

Answer:

3x^2+15x-1=0

Step-by-step explanation:

4/(3x+15)=4x

4=12x^2+60x

12x^2+60x-4=0

3x^2+15x-1=0

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5 0
2 years ago
Determine the equation of the line that passes through the point (7, -23)and is perpendicular to the line y=1/3x-6Enter your ans
marishachu [46]

We have a line y = 1/3x -6

We want a line that is perpendicular to this line

Perpendicular lines have slopes that multiply to -1

1/3 * m = -1

3 * 1/3 *m = -1 * 3

m = -3

The slope of the perpendicular line is -3

y = mx+b where m is the slope and b is the y intercept

y = -3x+b

We have a point on the line ( 7 ,-23)

Substitute this point into the equation

-23 = -3(7)+b

-23 = -21+b

Add 21 to each side

-23+21 = -21+21+b

-2 = b

y = -3x-2

In slope intercept form, the line perpendicular passing through (7,-23) is

y = -3x-2

3 0
1 year ago
Solve for b. (g+l)b=n
denis23 [38]

Answer:

         n

b = ---------

      (g+l)

Step-by-step explanation:

We need to isolate b.  Starting from (g+l)b=n, we divide both sides by (g+l), obtaining

         n

b = ---------

      (g+l)

7 0
3 years ago
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