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Nana76 [90]
3 years ago
6

Suppose both factors in a multiplication problem are multiples of 10. Why might the number of zeroes in the product be different

than the total number of zeroes in the factors?
Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

Multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

Step-by-step explanation:

Let the first five multiples of ten be

10*1= 10

10*2= 20

10*3=30

10*4=40

10*5= 50

Suppose we chose 20 and 50.

Now multiplying 20 with 50 we get

20*50= 1000

IF we count the total number of zeros in the factors ( 20 and 50) they are 2.

But the number of zeros in the product (1000) are 3.

This is because when we multiply 2 with 5 we get 10 which adds to the existing number of zeros ( i.e 2) and we get a total of 3 zeros.

And multiplying 10 with 50 we get

10*50= 500

IF we count the total number of zeros in the factors ( 10 and 50) they are 2.

But the number of zeros in the product (500) are also 2.

This is because when we multiply 1 with 5 we get 5 which does not add to the existing number of zeros ( i.e 2) and the total number of zeros remain the same.

Similarly multiplying 20 with 30 we get

20*30= 600

IF we count the total number of zeros in the factors ( 20 and 30) they are 2.

But the number of zeros in the product (600) are also 2.

This is because when we multiply 2 with 3 we get 6 which does not have a zero and the total  number of zeros remain the same as in the factors.

So we see that multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

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malfutka [58]

Answer:

0.156

Step-by-step explanation:

Using binomial probability formula, we have :

P( a out of n ) =ⁿCₐ x pᵃ x qⁿ⁻ᵃ  ------------------------------------------------- (1)

Where n = total number of sample

           a = number of success

            p = probability of success

            q = probability of failure

            n-a = number of failures

From the question:

n =10 , a = 7, p=0.54, q = 1-p = 0.46

Substituting into equation (1) we have:

P (7 out of 10) =  ¹⁰C₇ x (0.54)⁷x (0.46)¹⁰⁻⁷

                      = 0.1563

                     ≈ 0.156

                   

8 0
3 years ago
4(4-w)=3(2w+2)<br>find w​
Travka [436]

Answer:

1

Step-by-step explanation:

4(4-w) = 3(2w+2)

Use distributive property:

16 - 4w = 6w + 6

    +4w  +4w

------------------------

     16 = 10w + 6

    -6              -6

-------------------------

        10 = 10w

        ----    -----

        10      10

         1 = w

Hope this helped.

7 0
3 years ago
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I need some help with my math test today!
vladimir1956 [14]

Answer:

1.end point continues in one direction

2. point were two line segemnt, lines, rays meet

3. measures 90 degrees

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6. position in space

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Step-by-step explanation:

5 0
3 years ago
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A rectangular piece of land is 73/3 meter long and 61/4 meter wide.Find it's perimeter. Please solve it
Strike441 [17]

Answer:

49 1/6 meters

Step-by-step explanation:

P = 2(73/3) + 2(61/4)

= 146/3 + 61/2

= 48 2/3 + 30 1/2

= 48 4/6 + 30 3/6

= 48 + 7/6

= 48 + 1 1/6

= 49 1/6

5 0
3 years ago
Read 2 more answers
AB = 3 + x
strojnjashka [21]

Answer:

Option A) 4, 2

Step-by-step explanation:

We are given that quadrilateral ABCD is a  parallelogram with sides:

AB = 3 + x\\DC = 4x\\AD = y + 1\\BC = 2y

Since the opposite sides of a parallelogram are equal, we can write:

AB = DC\\AD=BC

Equating the sides we get,

\Rightarrow 3+x = 4x\\4x-x = 3\\3x = 3\\x = 1\\\Rightarrow y + 1 = 2y\\y = 1

Putting the values of x and y, we get:

AB = 3 + x =4\\DC = 4x =4\\AD = y + 1=2\\BC = 2y=2

Thus, the lengths of the opposite side pairs is 4,2.

4 0
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