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stealth61 [152]
3 years ago
9

Please help with trig homework

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0

Triangle BCD is similar to triangle ACE, so corresponding side lengths are proportional to one another and we have

\dfrac34=\dfrac{5.2}{5.2+x}

Solve for x:

3(5.2+x)=4\cdot5.2\implies15.6+3x=20.8\implies3x=5.2\implies x\approx1.73

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5 37/40 as a decimal
Luden [163]
Well 5=5
and 37/40
hmm, try to get that 40 into an nice number that is multiplule of 10
if we divide top and bottom by 4 that would work
( \frac{37}{40})( \frac{ \frac{1}{4} }{ \frac{1}{4} })= \frac{9.25}{10}
9.25/10=92.5=100=925/1000=925 thousandths=0.925

so the decimal would be 5.925
5 0
4 years ago
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Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?
Korvikt [17]

Remember that to factoring by grouping, we should split the expression into tow pairs that have something in common. The idea is that after factoring each pair, we get a binomial common factor. Is worth pointing out that you can pair factors in more than one way.

Let's check how to determine the factors of our expression by grouping:

Step 1. Look for common multiples between the terms.

Notice that 4 and 8 are multiples of 2, 8 is a multiple of 4, and all of them are multiples of 1, so we are going to try more than one pairing combination.

Step 2. Look for common factors between the variables.

Usually, we want to pair variables with higher exponents so when we factor each pair, we end up with another common factor in binomial form.

Step 3. Factor each pair; if you end with another binomial common factor, you nailed it. If not, try again.

Les't apply our steps to our expression 4x^3+x^2-8x-2

Applying step 1, we are pairing 4x^3 and -8x. Remember to pair the remaining factors as well.

(4x^3-8x)+(x^2-2)

The common factor in the first pair is 4x, so lets factor that out

4x(x^2-2)+(x^2-2)

Look! we have the binomial common factor (x^2-2). Unfortunately, 4x(x^2-2)+(x^2-2) is not in our given choices, so let's try again:

This time we are going to group the higher variables (step 2) 4x^3 and x^2

4x^3+x^2-8x-2

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The common factor in the first pair is x^2, and the common factor in the second one is -2, so let's factor out both of them:

(4x^3+x^2)+(-8x-2)

x^2(4x+1)-2(4x+1)

This time, we got option A.

We can conclude that the correct answer is: A) x2(4x + 1) – 2(4x + 1)

3 0
3 years ago
What are the x and y intercepts for the graph of 5x-2y=20
Mrac [35]
Divide by 20 to put the equation into intercept form.
.. x/4 +y/(-10) = 1

The x-intercept is 4.
The y-intercept is -10.

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