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gayaneshka [121]
4 years ago
10

Solve 5^x=81. 2Round to the nearest ten-thousandth. X≈????

Mathematics
1 answer:
Jet001 [13]4 years ago
7 0
Is that 5^x=81.2?

5^x=81.2  take the natural log of both sides

xln5=ln81.2  divide both sides by ln5

x=ln81.2/ln5

x≈2.7320  (to nearest ten-thousandth)

If you just meant 5^x=81, the process is the same

5^x=81  take the natural log of both sides

xln5=ln81  divide both sides by ln5

x=ln81/ln5

x≈2.7304  (to nearest ten-thousandth)


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Given data:

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