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melisa1 [442]
3 years ago
7

13. Tessa argues that the absolute value of -24 is greater than the opposite of -18. Is Tessa correct or not? Justify your think

ing.
1 point
A. Tessa is correct because |-24| = 24, the opposite of -18 is 18, and 24 > 18.
B. Tessa is incorrect because |-24| = -24, the opposite of -18 is 18, and 18 > -24.
C. Tessa is correct because |-24| = 24, the opposite of -18 is -18, and 24 > -18.
D. Tessa is incorrect because |-24| = 24, the opposite of -18 is 18, and -18 > 24.
Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

The answer is A.

Step-by-step explanation:

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39 POINTS!! I NEED HELP ASAP!!!!!!! 2 QUESTIONS!!!!!
dangina [55]

Answer: 1) A = 28ft^{2}

2) 55 points

Step-by-step explanation:

1) A= 8w + 18, w=1.25

A = 8(1.25) + 18

A = 10 + 18

A = 28ft^2

2) 25 points to start with, additional 5 points per magazine they sell, m = number of magazines they sell

total points = 25 + 5m

How many if they sell 6?

total = 25 + 5(6)

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3 years ago
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How many 2/3 penuts can be made with 8 ounces of penuts?
Sever21 [200]
Divide
8/1 / 2/3
Keep change flip
8/1 x 3/2
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He can make 12 2/3 ounce peanuts with 8 ounces of peanuts.
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3 years ago
Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

8 0
3 years ago
A circle has the equation 2x²+12x+2y²−16y−150=0.
KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

(x-h)^{2} +(y-k)^{2}=r^{2} (1)

Where (h,k) are the coordinates of the center and r is the radius.

Now, we are given the equation of this circle as follows:

2x^{2}+12x+2y^{2}-16y-150=0 (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

2(x^{2}+6x+y^{2}-8y-75)=0 (3)

Rearranging the equation:

x^{2}+6x+y^{2}-8y=75 (4)

(x^{2}+6x)+(y^{2}-8y)=75 (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of (a\pm b)^{2}=a^{2}\pm+2ab+b^{2}:

<u>For the first parenthesis:</u>

x^{2}+6x+b^{2}

We can rewrite this as:

x^{2}+2(3)x+b^{2}

Hence in this case b=3 and b^{2}=9:

x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}

<u>For the second parenthesis:</u>

y^{2}-8y+b^{2}

We can rewrite this as:

y^{2}-2(4)y+b^{2}

Hence in this case b=-3 and b^{2}=9:

y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}

Then, equation (5) is rewritten as follows:

(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16 (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

(x-3)^{2}+(y-4)^{2}=100 (7)

At this point we have the circle equation in the center radius form (x-h)^{2} +(y-k)^{2}=r^{2}

Hence:

h=-3

k=4

r=\sqrt{100}=10

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