Can someone please help me and explain? please

Mathematics

1 answer:

mariarad [96]2 years ago

4 0

Composite figure is made up of 4 triangles and a square.

Area of Square = Length x Length
Area of Square = 12 x 12
Area of Square= 144 cm²

Area of triangle = 1/2 x base x height
Area of triangle = 1/2 x 12 x 8
Area of triangle = 48 cm²

Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²

Total Area = 144 + 192 = 336 cm²

$\Longrightarrow \boxed { \boxed { Answer : 336 cm^{2} }}$

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Hey can you please help me posted pictureof question

pishuonlain [190]

There are two 5's because the 5 section takes up the amount of 2 sections.

There is a total of 8 sections because sections 2 and 5 take up the amount of 2 sections

5's to total = 2/8 = 1/4

Your answer is A. 1/4

Hope this helps :)

8 0

2 years ago

Pls help just please will mark BRAINLIEST

Darina [25.2K]

Answer:

44.2545

Step-by-step explanation:

you can find the third angle by taking 180-(90+55)=a

a=35

use law of sines

Sin(angle)/(opposite side of angle)=Sin(another angle)/(opposite side of another angle)

so, sin(a)/A=sin(b)/B

sin(35)/33=sin(55)/x

x=sin(55)/(sin(35)/33)

x=44.2545

Hope this helps :)

3 0

2 years ago

How do I solve this

Alina [70]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\displaystyle\sum \limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf S_{20}=\displaystyle\sum \limits_{n=1}^{\stackrel{\stackrel{n}{\downarrow }}{20}}~\stackrel{\stackrel{a_1}{\downarrow }}{3}(\stackrel{\stackrel{r}{\downarrow }}{1.5})^{n-1}\implies S_{20}=3\left(\cfrac{1-1.5^{20}}{1-1.5} \right)\implies S_{20}=3\left(\cfrac{1-\stackrel{\approx}{3325.3}}{-0.5} \right) \\\\\\ S_{20}=3\left(\cfrac{-3324.3}{-0.5} \right)\implies S_{20}=3(6648.6)\implies S_{20}=19945.8$