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2 years ago

Please hurry!!! given g(x) = -x - 2, find g(3)

Mathematics

1 answer:

baherus [9]2 years ago

5 0

Answer:

-5

Step-by-step explanation:

Plug in 3 as x:

g(x) = -x - 2

g(3) = -3 - 2

g(3) = -5

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The sum of the real numbers x and y is 11. Their difference is 5. What is the value of xy

Veseljchak [2.6K]

Answer:

x=6 y=5

Step-by-step explanation:

3 0

2 years ago

An athlete completes a race in 55.72 seconds. How many times greater is the digit in the tens place than the digit in the ones p

MArishka [77]

As they are the same the answer is 1 times

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2 years ago

At the end of each week, an employer gives some vacation hours to a few randomly selected employees. There are 25 employees in h

densk [106]

Answer: There are 177100 possible groups.

Step-by-step explanation:

Given: Total employees = 25

Number of employees wants to choose = 6

The combination of n things taken r at a time is given by:-

$^nC_r=\frac{n!}{r!(n-r)!}$

Put n = 25 and r= 6, we get

$^{25}C_6=\frac{25!}{6!(25-6)!}\\\\=\frac{25\times24\times23\times22\times21\times20\times19!}{6!19!}\\\\=177100$

Hence, there are 177100 possible groups.

8 0

2 years ago

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

2 years ago

Quadrilateral ABCD with vertices A(-9, 2), B(-8, 8), C(-4, 6), and D(-2, 2) is shown. You want to reflect quadrilateral ABCD in

telo118 [61]

Answer:

See explanation.

Step-by-step explanation:

Graph the quadrilateral. By inspection, you can tell where the midpoint is. (see attachment 1)

Now, I'll draw a line through it. (see attachment 2)

To reflect across a line, think about the points traveling across the line the same number of spaces the point is from the line. For example, point A is three away from the line. So, A' will be 3 away from the other side. The coordinates will be at (-3,2). (see attachment 3).

Do the same for the other points, and you'll have your image.

7 0

1 year ago