If reflected over y = x
<u>then use</u>
<u />![\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
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![\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}3&6&3\\-3&3&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%263%5C%5C-3%263%263%5Cend%7Barray%7D%5Cright%5D)
similar as (x, y) → (y, x)
<u>multiply the matrixes to get the final answer</u>
![\left[\begin{array}{ccc}(3*0+1*-3)&(6*0+1*3)&(3*0+1*3)\\(3*1+(-3*0)&(1*6+0*3)&(1*3+0*3)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%283%2A0%2B1%2A-3%29%26%286%2A0%2B1%2A3%29%26%283%2A0%2B1%2A3%29%5C%5C%283%2A1%2B%28-3%2A0%29%26%281%2A6%2B0%2A3%29%26%281%2A3%2B0%2A3%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}-3&3&3\\3&6&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%263%263%5C%5C3%266%263%5Cend%7Barray%7D%5Cright%5D)
Answer: You just need to draw a line
Step-by-step explanation: Place a dot on positive 2 on the y-axis, then go down 7 and 1 to the right. If it doesn’t go all the way down, make your own point to make it seem like it will land where it has to be and connect it to the positive 2. It has to be a straight line
The answer is
X^2+y^2+Dx+Ey+F=0
Answer:
Step-by-step explanation:
x^2 + 6x - 2x - 3
x^2 + 4x - 3
answer is C