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3 years ago

6

Matthew has 12 pencils . Three of them do not have erasers on the end . 4 are green .2 is orange .4 are brown .What fractions of

the M&Ms are brown

1 answer:

deff fn [24]3 years ago

7 0

You have given us no information whatsoever concerning the distribution
of M&Ms in Matthew's pencil box, so it's quite impossible to formulate any
sort of answer to the question.

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I’ll fine you brainlist if you answer please answer it’s URGENT

Marat540 [252]

Answer:

6, 0, 10

B

Step-by-step explanation:

Plug in the values of x into the equation to find the y coordinate. Then match the coordinates in the table to the graph.

8 0

3 years ago

Please somebody help me i need the answer

Daniel [21]

Answer:

B 2.25

Step-by-step explanation:

4 0

3 years ago

X-4y=-4<br> 5x – 4y= 12

vekshin1

Answer: {x,y} = {4,2}

[1] x - 4y = -4

[2] 5x - 4y = 12// Solve equation [1] for the variable x

[1] x = 4y - 4

// Plug this in for variable x in equation [2]

[2] 5•(4y-4) - 4y = 12

[2] 16y = 32

// Solve equation [2] for the variable y

[2] 16y = 32

[2] y = 2

// By now we know this much :

x = 4y-4

y = 2

// Use the y value to solve for x

x = 4(2)-4 = 4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The centroid of a triangle is at (8, 7). One vertex of the triangle is at (0, 1). What is the midpoint of the side opposite this

RideAnS [48]

Answer:

(12,10)

Step-by-step explanation:

Let the midpoint of the side opposite this vertex have coordinates B(a,b)

We have the centroid at C(8,7) and the vertex of the triangle at A(0,1).

The centroid divides AB internally in the ratio 2:1

We use the formula:

$(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})$

where m:n=2:1 is the ratio of internal division.

We substitute the coordinates of A and B and the ratio to get:

$(\frac{2a+1*0}{2+1},\frac{2b+1*1}{2+1})$

This should simplify and give us the centroid.

$(\frac{2a}{3},\frac{2b+1}{3})=(8,7)$

This implies that:

$\frac{2a}{3}=8,\frac{2b+1}{3}=7$

We solve for a and b

$2a=24,2b+1=21$

$a=12,b=10$

Therefore the midpoint of the side opposite this vertex is (12,10)

7 0

4 years ago

1. A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a co

slega [8]

Answer:

a) $83.3\ lb/in^2$

b) $12000\ lb/ft^2$

Step-by-step explanation:

Given : A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a concrete slab.

To find : Determine the stress that the base plate exerts on the concrete slab. Express your answer in units of (a) lb/in². and (b) lb/ft².

Solution :

a) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting ft into inches,

1 feet = 12 inch

2 feet = 2×12= 24 inch

The area of the rectangular base is $A=l\times b$

$A_1=24\times 9$

$A_1=216\ in^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_1}$

$S=\frac{18000\ lb}{216\ in^2}$

$S=83.3\ lb/in^2$

b) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting inches into ft,

1 inch = $\frac{1}{12}\ ft$

9 feet = $\frac{9}{12}=0.75\ ft$

The area of the rectangular base is $A=l\times b$

$A_2=2\times 0.75$

$A_2=1.5\ ft^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_2}$

$S=\frac{18000\ lb}{1.5\ ft^2}$

$S=12000\ lb/ft^2$

5 0

3 years ago