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asambeis [7]
3 years ago
6

Matthew has 12 pencils . Three of them do not have erasers on the end . 4 are green .2 is orange .4 are brown .What fractions of

the M&Ms are brown
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

You have given us no information whatsoever concerning the distribution
of M&Ms in Matthew's pencil box, so it's quite impossible to formulate any
sort of answer to the question.


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Find the equation of the line that is perpendicular to x - y = -5 and passes through (4, 7).
Ivanshal [37]
X - y = -5
-y = -x - 5
y = x + 5...slope here is 1. A perpendicular line will have a negative reciprocal slope. All that means is flip ur slope and change the sign. So our perpendicular line will have a slope of -1.

y = mx + b
slope(m) = -1
(4,7)...x = 4 and y = 7
now we sub and find b, the y int
7 = -1(4) + b
7 = -4 + b
7 + 4 = b
11 = b

so ur perpendicular equation is : y = -x + 11 <==
8 0
3 years ago
Simplify fully<br> 2√3 x 3√8​
OverLord2011 [107]

Answer: 12√6

Step-by-step explanation:

Given the expression;

2√3 * 3√√8

= (2*3) * (√3*√8)

= 6 * (√24)

= 6 * √4*6

= 6 * (2√6)

= (6*2)√6

= 12√6

Therefore, the simplified form of the expression is 12√6.

8 0
2 years ago
Sarah's Shipping and Ryan's Mail Services both ship packages. Sarah's trucks
algol [13]

Answer:I think 11

Step-by-step explanation: 11 because one can do no more than 11 packages so the most potential one most be 11 since it can't do 18 but the 18 can do 11 and the max of the other one is 11

8 0
3 years ago
State the domain of the rational function. f(x)= 7/14-x
34kurt
The denominator is 14-x.
Since the denominator cannot be equal to zero, you take the denominator, set it equal to zero, and solve.
This ill give you the value or values that must be eliminated (cannot be in the domain).

14 - x = 0
add x to both sides
14 = x
The domain is x ≠ 14
OR
(- ∞, 14) ∪ (14, ∞)
OR
All real numbers except 14
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3 years ago
I did the no question and 86 through 88
kolbaska11 [484]
86. D. -10
87. H. -6, -3, 0, 2
88. Quadrant 1
4 0
3 years ago
Read 2 more answers
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