Answer:
=m2+6mn+9n2
Step-by-step explanation:
=(m+3n)(m+3n)
=(m)(m)+(m)(3n)+(3n)(m)+(3n)(3n)
=m2+3mn+3mn+9n2
Answer:
Step-by-step explanation:
35.7826087
I'm guessing you want it estimated to the nearest tenth so 35.8
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Day 3 is double than day two judging by hours baked... it's 96 cookies