Question

Find the vertex of the function h(x) = -x^2 + 14

Answer 1

The vertex form:

$f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex$

$h(x)=-x^2+14=-(x-0)^2+14\to h=0,\ k=14$

Answer: (0, 14).