3 years ago

Find the vertex of the function h(x) = -x^2 + 14

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

The vertex form:

$f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex$

$h(x)=-x^2+14=-(x-0)^2+14\to h=0,\ k=14$

<h3>Answer: (0, 14).</h3>

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