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s344n2d4d5 [400]

2 years ago

14

Find the vertex of the function h(x) = -x^2 + 14

1 answer:

Mazyrski [523]2 years ago

5 0

The vertex form:

$f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex$

$h(x)=-x^2+14=-(x-0)^2+14\to h=0,\ k=14$

<h3>Answer: (0, 14).</h3>

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P(x) = 2x^3+5x -19 if x=2

AfilCa [17]

I think the answer is 2p = 7

7 0

2 years ago

FInd the value of x.<br> Y<br> D<br> W<br> X<br> (15x-8)<br> X =<br> N<br> 226

Oksi-84 [34.3K]

Let's start with the given arc and its angle.

The angle YWX is going to be half the arc length.

YWX = 1/2 (226) = 113

Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.

(15x - 8) + 113 = 180

15x + 105 = 180

15x = 75

x = 5

Hope this helps!

8 0

2 years ago

HELP WITH THESE QUESTIONS PART 2... 1 Question

Lunna [17]

<u>Step-by-step explanation</u> and Answers:

$(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}})$ is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = $\sqrt{10}$

sin = $\frac{opposite}{hypotenuse}$ = $\frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{3\sqrt{10}}{10}$

cos = $\frac{adjacent}{hypotenuse}$ = $\frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{\sqrt{10}}{10}$

tan = $\frac{opposite}{adjacent}$ = $\frac{3}{1}$ = 3

csc = $\frac{hypotenuse}{opposite}$ = $\frac{\sqrt{10}}{3}$

sec = $\frac{hypotenuse}{adjacent}$ = $\frac{\sqrt{10}}{1}$ = $\sqrt{10}$

cot = $\frac{adjacent}{opposite}$ = $\frac{1}{3}$

7 0

3 years ago

15 is subtracted from a number and the difference is divided by 17. If the quotient is 4 and there is

GREYUIT [131]

Answer:

83

Step-by-step explanation:

6 0

2 years ago

At the end of her work day at the Ferguson Corporation, Sarah usually

Naddik [55]

Answer:

1263.7032 feets

Step-by-step explanation:

Distance from Ferguson corporation to Springdale Town center ; let the distance = x

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 27 = x / 2000

0.5095254 * 2000 = x

1019.0508 feets

Distance from Springdale to Subway station, this is the hypotenuse :

Hypotenuse = √(1019.0508² + 2000²)

Hypotenuse = √5038464.7

Hypotenuse = 2244.6524 feets

Total distance walked from Ferguson to Springdale, then to Subway ;

(1019.0508 + 2244.6524) feets = 3263.7032 feets

Additional distance walked :

(3263.7032 feets - 2000 feets) = 1263.7032

6 0

2 years ago