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tia_tia [17]
3 years ago
10

How can you tell when a quadratic equation has two identical, rational solutions?. a:when the radicand is negative. b:when the r

adicand is not a perfect square. c:when b in the quadratic formula is greater than the radicand. d:when the radicand equals zero
Mathematics
2 answers:
sergey [27]3 years ago
4 0
"When the radicand equals zero" is the one among the following choices given in the question that you can tell when <span>a quadratic equation has two identical, rational solutions. The correct option among all the options that are given in the question is the fourth option or option "d". I hope the answer has helped you.</span>
Deffense [45]3 years ago
4 0
<h2>Answer:</h2>

The  quadratic equation has two identical, rational solutions:

d:      when the radicand equals zero.

<h2>Step-by-step explanation:</h2>

We know that the general quadratic equation of the type:

ax^2+bx+c=0

The solution is given by:

x=\dfrac{-b\pm \sqrt{D}}{2a}

with discriminant:

D=b^2-4ac

has:

  • Two rational and identical solution if the radicand i.e. D is equal to zero.
  • Two rational and unequal solution if the radicand i.e. D is strictly greater than zero.
  • Two imaginary solution if the radicand i.e. D is strictly less than zero.

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Step-by-step explanation:

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I need help with this question.
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3 years ago
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5 0
4 years ago
Which linear equations does the graph show the solution to? Select all that apply. y = 2x + 13 y = –x – 2 y = 3x – 5 y = negativ
salantis [7]

Answer:

y = 2x + 13

y = –x – 2

Step-by-step explanation:

The options are:

y = 2x + 13

y = -x - 2

y = 3x - 5

y= -(1/2)x + 6

y = -2x - 2

The graph is shown in the figure attached. There, point (-5, 3) is shown. Replacing it into the equations we get:

y = 2(-5) + 13  = 3    (so, it is a solution)

y = -(-5) - 2 = 3     (so, it is a solution)

y = 3(-5) - 5  = -20 ≠ 3   (so, it isn't a solution)

y= -(1/2)(-5) + 6  = 8.5 ≠ 3     (so, it isn't a solution)

y = -2(-5) - 2 = 8 ≠ 3     (so, it isn't a solution)

6 0
4 years ago
Read 2 more answers
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