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tia_tia [17]
3 years ago
10

How can you tell when a quadratic equation has two identical, rational solutions?. a:when the radicand is negative. b:when the r

adicand is not a perfect square. c:when b in the quadratic formula is greater than the radicand. d:when the radicand equals zero
Mathematics
2 answers:
sergey [27]3 years ago
4 0
"When the radicand equals zero" is the one among the following choices given in the question that you can tell when <span>a quadratic equation has two identical, rational solutions. The correct option among all the options that are given in the question is the fourth option or option "d". I hope the answer has helped you.</span>
Deffense [45]3 years ago
4 0
<h2>Answer:</h2>

The  quadratic equation has two identical, rational solutions:

d:      when the radicand equals zero.

<h2>Step-by-step explanation:</h2>

We know that the general quadratic equation of the type:

ax^2+bx+c=0

The solution is given by:

x=\dfrac{-b\pm \sqrt{D}}{2a}

with discriminant:

D=b^2-4ac

has:

  • Two rational and identical solution if the radicand i.e. D is equal to zero.
  • Two rational and unequal solution if the radicand i.e. D is strictly greater than zero.
  • Two imaginary solution if the radicand i.e. D is strictly less than zero.

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I need to Match each equation that represents each situation.
almond37 [142]

Step-by-step explanation:

this is quite easy, when you use just common sense and identify the right numbers and variable names.

they is nothing special needed, you don't even need to create the equations yourself.

$4.99 per pound. buys b pounds and pays $14.95.

14.95 = 4.99 × b

$4.99 per pound. buys b pounds and pays c.

this is exactly the same as before, just that this time the total amount is not given as a constant but as a variable.

c = 4.99 × b

d dollars per pound. buys b pounds and pays t.

the same as the 2 cases before, just now everything is a variable. no more constants, but otherwise the completely same structure and method.

t = d × b

earned $275, which is $45 more than Noah ("n").

$275 = n + $45

earned m dollars, which is $45 more than Noah ("n").

m = n + $45

earned m dollars, which is y dollars more than Noah (we are asked that Noah's earnings are now called "v").

here your teacher made a mistake.

sure, the only remaining answer is

v = m + y

but it is not correct. given the names of the prime and associated variables the correct answer would be

m = v + y or v = m - y

7 0
2 years ago
The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand
alexira [117]

Answer:

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }  

            t = <em>1.076</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Mean of the Population (μ) = 8.0

<em>Mean of the sample (x⁻) = 8.25</em>

Given data

                  8,9,9,8,8,9,8,7

Given sample size  n= 8

Given sample standard deviation(S) = 0.661

<u><em>Step(ii):-</em></u>

<em>Null hypothesis : H:  (μ) = 8.0</em>

<em>Alternative Hypothesis :H:(μ) > 8.0</em>

<em>Degrees of freedom = n-1 = 8-1=7</em>

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }<em></em>

<em>              </em>t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }<em></em>

<em>            t =  1.076</em>

<em>Critical value </em>

<em>                    t₍₇,₀.₀₅₎   = 2.3646</em>

<em>The calculated value   t =  1.076 < 2.3646 at 0.05 level of significance</em>

<em>Null hypothesis is accepted</em>

<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>

<em></em>

3 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
A diver is a horizontal distance of 50 feet from a boat and 120 feet beneath the surface of the water. What distance will the di
amid [387]

Answer:

The answer is 130 feet

Step-by-step explanation:

Using Pythagoras' Theorem:

120² + 50² = diagonal²

diagonal² = 16900ft

diagonal = √16900

= 130ft

(Correct me if i am wrong)

4 0
3 years ago
This one too i need help with all of them
bearhunter [10]
B would be your answer
5 0
3 years ago
Read 2 more answers
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